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PtichkaEL [24]
4 years ago
10

3 4 6 9 13 18 24 what is next

Mathematics
1 answer:
Eva8 [605]4 years ago
3 0
31 it adds up like 1-2-3-4-5-6-7-8-9 so 3+1=4 +2=6+3=9+4=13 and so on

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Write an expression for the calculation, divide 10 in half and subtract from 50 divided into fifths
allsm [11]
[(10/.5)-50]/5
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You have 6 donuts and you want to give 2/3 of them to a friend and keep 1/3 for yourself. How many donuts would your friend get?
Furkat [3]
4 donuts because you can change the denominator to 6 and get 4/6 and thats how you get 4
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Can someone please help me with my homework please.p
umka2103 [35]

Answer:

8-20c

Step-by-step explanation:

Just plug 4c into the function

8-5x

8-5(4c)

8-20c

4 0
4 years ago
Pam has 90 m of fencing to enclose an area in a petting zoo with two dividers to separate three types of young animals. The thre
andrew-mc [135]

Answer:

The area function is

A=\frac{135}{2}x-\frac{9}{2}x^2.

The domain and range of A is (0,15m) and (0, 253.125 m^2].

Step-by-step explanation:

The given length of fencing is 90 m.

Let the length and width of each pen be x and y respectively as shown in the figure.

As there are 3 pens, so, the total area,

A= 3 xy \;\cdots (i)

From the figure the total length of fencing is 6x+4y.

Here, for a significant area for the animals, x>0 as well as y>0 as x and y are the sides of ben.

From the given value:

6x+4y=90\;\cdots (ii)

\Rightarrow  y=\frac {45}{2}-\frac{3x}{2}

Now, from equation (i)

A=3x\left(\frac {45}{2}-\frac{3x}{2}\right)

\Rightarrow A=\frac{135}{2}x-\frac{9}{2}x^2\;\cdots (iii)

This is the required area function in the terms of variable x.

For the domain of area function, from equation (ii)

x=15-\frac{2y}{3}

\Rightarrow x [as y>0]

So, the domain of area function is (0,15m).

For the range of area function:

As x \rightarrow 0 or y\rightarrow 0, then A\rightarrow 0 [from equation (i)]

\Rightarrow A>0

Now, differentiate the area function with respect to x .

\frac {dA}{dx}=\frac{135}{2}-9x

Equate \frac {dA}{dx}  to zero to get the extremum point.

\frac {dA}{dx}=0

\Rightarrow \frac{135}{2}-9x=0

\Rightarrow x=\frac{15}{2}

Check this point by double differentiation

\frac {d^2A}{dx^2}=-9

As,  \frac {d^2A}{dx^2}, so, point x=\frac{15}{2} is corresponding to maxima.

Put this value back to equation (iii) to get the maximum value of area function. We have

A=\frac{135}{2}\times \frac {15}{2}-\frac{9}{2}\times \left(\frac {15}{2}\right)^2

\Rightarrow A=253.125 m^2

Hence, the range of area function is (0, 253.125 m^2].

4 0
4 years ago
A cylinder with a diameter of 10 inches (in.) and a cube are shown.
Scorpion4ik [409]

Answer:

C

Step-by-step explanation:

the volume of the cylinder is 3769.91

the volume of the cube is 1000

so the cylinder's volume is clearly larger than the cube's volume.

7 0
3 years ago
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