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lilavasa [31]
3 years ago
7

Can help me for homework pleas

Mathematics
2 answers:
n200080 [17]3 years ago
8 0

Please can you help me in 19 answer i coudnt do it

Rasek [7]3 years ago
6 0
Hey You!

32 / 8 = 4

4 × 7 = 28

20. ANSWER:

The fish swims 28 feet deep.

21. ANSWER:

Numerator;Denominator

22. ANSWER:

439 / 3 = 146.3333 repeat.

So, each individual computer costs more than each individual printer.

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find the variance and standard deviation of the given set of data to the nearest tenth. 440,130,280,500,150,640,760
Westkost [7]

Answer:

The variance is 49595.9

The standard deviation is 222.7

Step-by-step explanation:

The step -by -step explanation is shown in the picture above.

8 0
3 years ago
Solve the equation for real c variable. R-C=p
tekilochka [14]

C = R - p

add C to both sides

R = C + p

subtract p from both sides

R - p = C ⇒ C = R - p


3 0
3 years ago
A four-digit number N leaves a remainder of 10 when divided by 21, a remainder of 11 when divided by 23, and a remainder of 12 w
aksik [14]

Answer:

  16

Step-by-step explanation:

There may be a formal way to solve simultaneous Diophantine equations, but I don't know what it is. So, I addressed this by solving them 2 at a time.

First of all, we want to find a relation between integers p and q such that ...

  21p+10 = 23q +11

  21p -23q = 1 . . . . . . subtract 23q+10

Using the extended Euclidean algorithm or trial and error or astute observation, we find that (p, q) = (11, 10) is a solution to this equation. Then we can write p and q as ...

  • p = 23n+11
  • q = 21n+10

for some integer n.

Then our original numbers become ...

  21p+10 = 21(23n+11)+10 = 483n +241 . . . . for some integer n

For this to be a 4-digit number, we must have n such that

  1000 ≤ 483n +241 ≤ 9999

  1.6 < n < 20.2

__

Modulo 25, the number (483n+241) is ...

  8n +16

and we want that value to be 12:

  (8n +16) mod 25 = 12

  (8n +4) mod 25 = 0 . . . . . subtract 12

  4(2n+1) mod 25 = 0 . . . .  factor out 4

For this to be true, we must have 2n+1 be a multiple of 25. The only value of n that is in the required interval [2, 20] is n=12.

__

When n=12, 483n+241 = 6037. The sum of digits of 6037 is 16.

3 0
3 years ago
Find two numbers such that the sum of the first and three times the second is 5 and the sum of the second and two times the firs
Sav [38]

Answer:

first number= 19/5

second number= 2/5

Step-by-step explanation:

first number= a

second number= b

a+3b=5   equation 1

b+2a=8  equation 2

using equation 2 we have

b=8-2a

using equation 1 we have

a+3(8-2a)=5  

a+24-6a=5

24-5=6a-a

19=5a

a=19/5 = first number

so using b=8-2a

we have

b=8-2(19/5)

b=8-(38/5)

b=2/5 = second number

4 0
3 years ago
How Do I solve -7(2v-2)+4v=4(v+1)
diamong [38]
V = 5/7 in fraction from and in decimal form 0. 714285 . Hope this helped . Please mark me brainliest
4 0
3 years ago
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