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garri49 [273]
3 years ago
14

How to find the vertex of a quadratic function?

Mathematics
2 answers:
slamgirl [31]3 years ago
6 0
The formula for a quadratic function is y=ax^2+bx+c.
The vertex is h, k. This can be found by evaluating y to get k, and dividung -b by a in order to get h.

Hope this helps!
scoray [572]3 years ago
3 0

Answer:Parabolas always have a lowest point. This point, where the parabola changes direction, is called the "vertex". If the quadratic is written in the form y = a(x – h)2 + k, then the vertex is the point (h, k).

Step-by-step explanation:

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Umnica [9.8K]

Answer:

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What is the range of the equation
a_sh-v [17]

The range of the equation is y>2

Explanation:

The given equation is y=2(4)^{x+3}+2

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

y=2 \cdot 4^{x+3}+2

This can be written as y=2^{1+2(x+3)}+2

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

x=2^{1+2(y+3)}+2

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x-2=2^{1+2(y+3)}

Applying the log rule, if f(x) = g(x) then \ln (f(x))=\ln (g(x)), then, we get;

\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)

Simplifying, we get;

(1+2(y+3)) \ln (2)=\ln (x-2)

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2 y+7=\frac{\ln (x-2)}{\ln (2)}

Subtracting 7 from both sides of the equation, we have;

2 y=\frac{\ln (x-2)}{\ln (2)}-7

Dividing both sides by 2, we get;

y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}

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x-2>0

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Step-by-step explanation:

It is like you a=have 3 pencils and you give 1 to your friend how many will you have?

subtract 1 from 3

3-1=2

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inysia [295]

Step-by-step explanation:

X = 50+45 = 95 exterior angle

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