Answer:
AE=22.4
Step-by-step explanation:
BE is 1/2 of BC
BC is 20 cm All sides of a square are equal
BE = 1/2 BC Property of a midpoint.
BE = 10
Now just use Pythagorus
AB^2 + BE^2 = AE^2
AE^2 = 20^2 + 10^2 Perform the sqrs
AE^2 = 400 + 100 Add the terms
AE^2 = 500 Take the square root of both sides
√AE^2 = √500
AE = 22.36
AE ≈ 22.4
Let x be the money distributed to the first group and y be the money distributed to the second group.
Then, x + y = 1000
Let c be the money distributed to one child in the first group and b be the money distributed to one brother in the second group.
Then, x = 5c and y = 2b
Hence 5c + 2b = 1000.
The longest side of the triangle has to be less than the sum of the two other sides.
A ⇒ 7 + 8 = 15
B ⇒ 8 + 5 < 14
C ⇒ 6 + 3 < 10
D ⇒ 2 + 6 > 7
The answer is D, because the longest side length (7) is shorter than the two other side lengths (2 and 6).
Step-by-step explanation:
How to Calculate the Semi Interquartile Range / Quartile Deviation. As the SIR is half of the Interquartile Range, all you need to do is find the IQR and then divide your answer by 2. Note: You might see the formula QD = 1/2(Q3 – Q1). Algebraically they are the same.
Answer:
Leanna consumed 1,500 calories at dinner.
Step-by-step explanation:
We know that Leanna eats 2/3 of her daily calories at dinner, and we know that she eats 400 calories at breakfast and 350 calories at lunch. Assuming that these are the only times she is eating, then we can assume that the combination of her breakfast and lunch calorie consumption must equal 1/3 of her daily calories.
Let's let x represent the calories that Leanna consumes. Because she eats 2/3 at dinner, then her caloric consumption at dinner must be twice that from breakfast and lunch combined.
x = 2 (400 + 350)
x = 2 (750)
x = 1,500 calories
check:
Combining all calories gives us Leanna's total daily caloric consumption
750 + 1,500 = 2,250 calories in total
750 / 2,250 reduces to 1/3
1,500 / 2,250 reduces to 2/3
