Answer:
I don't know but this question feels incomplete
Part A:
Let the length of one of the sides of the rectangle be L, then the length of the other side is obtained as follow.
Let the length of the other side be x, then
Thus, if the length of one of the side is x, the length of the other side is 8 - L.
Hence, the area of the rectangle in terms of L is given by
Part B:
To find the domain of A
Recall that the domain of a function is the set of values which can be assumed by the independent variable. In this case, the domain is the set of values that L can take.
Notice that the length of a side of a rectangle cannot be negative or 0, thus L cannot be 8 as 8 - 8 = 0 or any number greater than 8.
Hence the domain of the area are the set of values between 0 and 8 not inclusive.
Therefore,
1. area of a pentagon when 1 side is x is
so if perimiter is 100 then one side is 100/5 or 20
area will be
≈<span>688.2 square yards
2. area of a hexagon when 1 side is length x is
so if permiter is 100 then length of one side is 100/6 or about 16.666666666666
the area will be
≈721.7 square yards
3. area of a regular octagon with side lenghts x is
so if 8 sides then side length of each is 100/8 or 12.5
area will be
≈754.4 square yards
octagon wil have most space
you can tell because the more sides it has, the more it gets to a circle and the more area it encloses with a given perimiter
</span>
Answer:
a. 9.2 x 10-2 M
Step-by-step explanation:
i took test
Answer:
Step-by-step explanation:
Given
See attachment for proper format of table
--- Sample
A = Supplier 1
B = Conforms to specification
Solving (a): P(A)
Here, we only consider data in sample 1 row.
In this row:
and
So, we have:
P(A) is then calculated as:
Solving (b): P(B)
Here, we only consider data in the Yes column.
In this column:
and
So, we have:
P(B) is then calculated as:
Solving (c): P(A n B)
Here, we only consider the similar cell in the yes column and sample 1 row.
This cell is: [Supplier 1][Yes]
And it is represented with; n(A n B)
So, we have:
The probability is then calculated as:
Solving (d): P(A u B)
This is calculated as:
This gives:
Take LCM