Answer:
I think it's A to your answer
Answer:
40.6??
Step-by-step explanation:
![\displaystyle\int_2^8g(x)\,\mathrm dx=12](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint_2%5E8g%28x%29%5C%2C%5Cmathrm%20dx%3D12)
![\displaystyle\int_6^8g(x)\,\mathrm dx=-3](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint_6%5E8g%28x%29%5C%2C%5Cmathrm%20dx%3D-3)
Use the fact that integrals are additive on their intervals. Mathematically, if
, then
![\displaystyle\int_a^bg(x)\,\mathrm dx=\int_a^cg(x)\,\mathrm dx+\int_c^bg(x)\,\mathrm dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint_a%5Ebg%28x%29%5C%2C%5Cmathrm%20dx%3D%5Cint_a%5Ecg%28x%29%5C%2C%5Cmathrm%20dx%2B%5Cint_c%5Ebg%28x%29%5C%2C%5Cmathrm%20dx)
So we have
![\displaystyle2\int_2^6g(x)\,\mathrm dx=2\left(\int_2^8g(x)\,\mathrm dx-\int_6^8g(x)\,\mathrm dx\right)=2(12-(-3))=30](https://tex.z-dn.net/?f=%5Cdisplaystyle2%5Cint_2%5E6g%28x%29%5C%2C%5Cmathrm%20dx%3D2%5Cleft%28%5Cint_2%5E8g%28x%29%5C%2C%5Cmathrm%20dx-%5Cint_6%5E8g%28x%29%5C%2C%5Cmathrm%20dx%5Cright%29%3D2%2812-%28-3%29%29%3D30)
Step-by-step explanation:
E = m/2g(v²-u²)
2g×E = 2g×m/2g(v²-u²)
2Eg = m(v²-u²)
2Eg = mv² - mu²
mu²= mv² -2Eg
mu²/m = mv² -2Eg /m
u²= v² -2Eg
u = √v²-√2Eg
Answer:
m∠BJK = 146
m∠IJB = 26
Step-by-step explanation:
m∠BJK + m∠IJB = m∠IJK
<em>146 </em>+2x + 2x +<em>26</em> = 172
<em> 172 </em> + 4x = 172
4x = 172 -172 = 0
x = 0
m∠BJK = 146
m∠IJB = 26