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An aircraft factory manufactures airplane engines. The unit cost (the cost in dollars to make each airplane engine) depends on t

Juliette [100K]

Answer:

Minimum unit cost = 5,858

Step-by-step explanation:

Given the function : C(x)=x^2−520x+73458

To find the minimum unit cost :

Take the derivative of C(x) with respect to x

dC/dx = 2x - 520

Set = 0

2x - 520

2x = 520

x = 260

To minimize unit cost, 260 engines must be produced

Hence, minimum unit cost will be :

C(x)=x^2−520x+73458

Put x = 260

C(260) = 260^2−520(260) + 73458

= 5,858

7 0

3 years ago

The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6

viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The proportion of contracts involved between five and 10 inclusive bidders is 0.5.

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders No. contracts Relative frequency of contracts

2 6 6/102=0.0588

3 20 20/102=0.1961

4 24 24/102=0.2353

5 18 18/102=0.1765

6 13 13/102=0.1275

7 7 7/102=0.0686

8 5 5/102=0.049

9 6 6/102=0.0588

10 2 2/102=0.0196

11 1 1/102=0.0098

Total 102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The proportion of contracts involved between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10= Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

8 0

3 years ago

mr covert went shopping at the grocery store with a 20 dollar bill in his pocket and left his wallet at home. write an equation

ELEN [110]

X= the amount of money he can spend

x=$20

8 0

3 years ago

Read 2 more answers

Sophia puts $250 in the bank with a 2.5% annual interest rate compounded monthly. If Sophia does not touch his money, how much m

Fittoniya [83]

Answer:

Step-by-step explanation:

Deposited amount initially (P) = $250.

Rate of interest(r) = 2.5% compounded monthly = 0.025

Number of years (t) = 4.

Number of months in an year (n) = 12.

Formula for compound interest:

$A=P(1+\frac{r}{n})^{nt}$ .

Plugging values in formula, we get

$A= 250(1+\frac{0.025}{12})^{12\times 4}$

$A= 250(1.00208)^{48}$

$A= 250\times \:1.10506$

A=276.26.

<h3>Therefore, correct option is D) $276.26.</h3>

7 0

3 years ago

in the following ordinary annuity interest is compounded with each payment and the payment is made at the end of the compounding

stealth61 [152]

Answer: $59313.58

Step-by-step explanation:

We know that formula we use to find the accumulated amount of the annuity ( ordinary annuity interest is compounded ) is given by :-

$FV=A(\frac{(1+\frac{r}{m})^{mt})-1}{\frac{r}{m}})$ , where A is the annuity payment deposit, r is annual interest rate , t is time in years and n is number of periods.

Given : Annuity payment deposit :A= $4500

rate of interest :r= 6%=0.06

No. of periods : m= 1 [∵ its annual]

Time : t= 10 years

Now we get,

$FV=(4500)(\frac{(1+\frac{0.06}{1})^{1\times10})-1}{\frac{0.06}{1}})\\\\\Rightarrow\ FV=(4500)(\frac{(1.06)^{10})-1}{0.06})\\\\\Rightarrow\ FV=(4500)(\frac{0.79084769654}{0.06})\\\\\Rightarrow\ FV=(4500)(13.1807949423)\\\\\Rightarrow\ FV=59313.5772407\approx59313.58 \ \$

∴ the accumulated amount of the annuity= $59313.58

4 0

4 years ago

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