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kozerog [31]
4 years ago
6

What is the effective resistance r of the two-resistor system? express the effective resistance in terms of r1 and r2?

Physics
1 answer:
Alekssandra [29.7K]4 years ago
4 0

As per the question, the resistor system contains two resistors.

The two resistors are denoted as r_{1}\ and\ r_{2}\ respectively

We are asked to calculate the effective resistance in terms of  r_{1}\ and\ r_{2}\ respectively

The two resistors can be connected in two ways.

CASE-1: Let the resistors are connected in series.

When the resistors are connected in series, the effective resistance is the algebraic sum of the individual resistors.

Hence, the effective resistance  r= r_{1} +r_{2}  [ans]

CASE-2: Let the resistors are connected in parallel.

The effective resistance is calculated as follows-

                                     \frac{1}{r}= \frac{1}{ r_{1}}+ \frac{1}{r_{2}}

                                            =\frac{r_{1}+ r_{2}} {r_{1} r_{2}}

                                   ⇒  r =\frac{r_{1} r_{2}} { r_{1} +r_{2}}  [ans]

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Answer:

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Explanation:

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A source injects an electron of speed v = 2.9 × 107 m/s into a uniform magnetic field of magnitude B = 1.7 × 10-3 T. The velocit
34kurt

Answer:

r = 0.664 m.

Explanation:

Let's write the equation of the magnetic force, the blacks syndicate vectors

       F = q v x B

From this expression we see that the force is perpendicular to the velocity and the field, so it is a centripetal force, the modulus of the force is

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We write Newton's second law

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Let's calculate

     r = 9.1 10-31 2.9 107 / (1.6 10-19 1.7 10-3 sin8.4)

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4 years ago
Find a numerical value for ρearth, the average density of the earth in kilograms per cubic meter. use 6378km for the radius of t
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Answer:

5501 kg/m^3

Explanation:

The value of g at the Earth's surface is

g=\frac{GM}{R^2}=9.70 m/s^2

where G is the gravitational constant

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R=6378km = 6.378 \cdot 10^6 m is the Earth's radius

Solving the formula for M, we find the value of the Earth's mass:

M=\frac{gR^2}{G}=\frac{(9.81 m/s^2)(6.378\cdot 10^6 m)^2}{6.67\cdot 10^{-11}}=5.98\cdot 10^{24}kg

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