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Jobisdone [24]
3 years ago
13

A ball is thrown so that its speed increases by 20 m/s in 10 seconds. What is the ball’s acceleration?

Physics
1 answer:
sp2606 [1]3 years ago
7 0

Answer: a= 2 m/s²

Explanation: acceleration = change of speed/ time = 20 m/s / 10 s

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A 5.00-g bullet is fired into a 900-g block of wood suspended as a ballistic pendulum. The combined mass swings up to a height o
Thepotemich [5.8K]

Answer:

The value is  KE_b =0.710 \ J

Explanation:

From the question we are told that

   The mass  of the bullet is m_b  = 5.00 \ g  = 0.005 \  kg

  The mass  of the wood is  m_w =  900 \  g  =  0.90\  kg

   The height attained by the combined mass is  h =  8.0 \ cm  =  0.08 \ m

Generally according to the law of energy conservation    

    KE _b  =  PE_c

Here KE_b is the kinetic energy of the bullet before collision.

and PE_c is the  potential  energy of the combined mass of bullet and wood at the height h which is mathematically represented as

      PE_m  =  [m_b  + m_w] *  g *  h

So

   KE_b =PE_c   = [0.005  + 0.90] * 9.8 *0.08

=> KE_b =0.710 \ J

3 0
3 years ago
Why is a control group generally very important in an experiment?
Alex17521 [72]

Answer: The control group is the part where you see what happens when you change a variable you want to study/examine. Basically, you need the control group because you need something to see what happens when you change something.

Hope this Helps! :))))

8 0
3 years ago
As you run toward a source of sound, you perceive the frequency of that sound to
Nata [24]

As you run toward a source of sound, you perceive the frequency of that sound to decrease.

<u>Explanation:</u>

Doppler's effect is a principle used to describe the frequency and the intensity of sound and wavelengths of a source and observer with the two possibilities.

(i) Stationary sound source and moving observer.

(ii) Moving sound source and a stationary observer. It is a relative motion.

Consider when the observer is moving towards a source, the frequency of the sound will be higher and when moving away from the source, the frequency will decrease.

5 0
4 years ago
Read 2 more answers
1. How much heat energy is required to raise the temperature of a 5 kg aluminium bar
Ray Of Light [21]

Answer:

180 kJ

Explanation:

Given that:

Mass (m) = 5 kg

Initial temperature (T1) = 28°C

Final temperature (T2) = 68°C

The change in temperature (ΔT) = T2 - T1 = 68°C - 28°C = 40°C

Specific heat capacity of aluminium (c) = 900 J/kg°C

The quantity of heat energy required (q) is given by:

q = mcΔT

q = 5 kg × 900 J/kg°C × 40°C

q =  180000 Joules

q = 180 kJ

Therefore 180 kJ is required to raise the temperature of aluminium from 28°C to 68°C.

5 0
3 years ago
Which of these measures a wavelength.
ch4aika [34]

Answer:

A

Explanation:

To measure wavelength, you would find the distance from crest (top of the wave) to crest.  

Hope this helps!  :)

8 0
3 years ago
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