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Mademuasel [1]
2 years ago
5

If the slowest instruction in the SCA executes in 12.5 ns, then what is maximum system clock frequency in MHz

Physics
1 answer:
Margaret [11]2 years ago
5 0

Since the slowest instruction in the SCA executes in 12.5 ns, the maximum system clock frequency is 80 MHz

To answer the question, we need to know what frequency is.

<h3>What is frequency?</h3>

Frequency is the number of oscillations per second of a wave.

It is given by f = 1/T where T = period of wave

Now, given that the slowest instruction in the SCA executes in t = 12.5 ns, we need to calculate maximum system clock frequency, f.

<h3>What is the maximum system clock frequency?</h3>

So, f = 1/t

= 1/12.5 ns

= 1/(12.5 × 10⁻⁹ s)

= 1/12.5 × 10⁹ Hz

= 0.08 × 10⁹ Hz

= 80 × 10⁻³ × 10⁹ Hz

= 80 × 10⁶ Hz

= 80 MHz

So, the maximum system clock frequency is 80 MHz

Learn more about maximum system clock frequency here:

brainly.com/question/14636488

#SPJ11

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There is a current of 0.83 A through a lightbulb in a 120 V circuit. What is the resistance of this lightbulb?
Lemur [1.5K]

Considering the Ohm's law, the resistance of the lightbulb is 144.58 Ω.

<h3>Definition of current</h3>

The flow of electricity through an object, such as a wire, is known as current (I). Its unit of measure is amps (A). So the current is a measure of the speed at which the charge passes a given reference point in a specified direction.

<h3>Definition of voltage</h3>

The driving force (electrical pressure) behind the flow of a current is known as voltage and is measured in volts (V) (voltage can also be referred to as the potential difference or electromotive force). That is, voltage is a measure of the work required to move a charge from one point to another.

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<h3>Ohm's law</h3>

Ohm's law establishes the relationship between current, voltage, and resistance in an electrical circuit.

This law establishes that the intensity of the current that passes through a circuit is directly proportional to the voltage of the same and inversely proportional to the resistance that it presents.

Mathematically, Ohm's law is expressed as:

I=\frac{V}{R}

Where:

  • I is the current measured in amps (A).
  • V the voltage measured in volts (V).
  • R the resistance that is measured in ohms (Ω).

<h3>Resistance of the lightbulb</h3>

In this case, you know that the voltage between two points in a circuit is 120 V and there is a current of 0.83 A.

Replacing in the Ohm's Law:

0.83A=\frac{120 V}{R}

Solving:

0.83 A× R=  120 V

R=\frac{120 V}{0.83A}

<u><em>R= 144.58 Ω</em></u>

Finally, the resistance of the lightbulb is 144.58 Ω.

Learn more about Ohm's law:

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