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melisa1 [442]
3 years ago
8

A box contains 3 plain pencils and 7 pens . A second box contains 4 colored pencils and 4 crayons . One item from each box is ch

osen at random . What is the probability that a pen from the first box and a crayon from the second box are selected ? Write your answer as a fraction in the simplest form
Mathematics
1 answer:
strojnjashka [21]3 years ago
6 0

Answer:

its 6 bc 7+3=10 4*4=16 16-10=6

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WHOEVER ANSWERS FIRST GETS BRAINLIEST PLSSSSS HELP MEH
chubhunter [2.5K]

Answer:

29

Step-by-step explanation:

7 1/4 + 9 3/4 = 17

6 1/4 + 5 1/2 = 12

17 + 12 = 29

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3 years ago
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|6-27| how the answer this question
sweet [91]

Answer:

First notice that they’re asking for the absolute value of the equation.

The absolute value is how far that number is from 0.

Basically it’s the number without a negative sign.

ok so 6-27 = -21

The product for 6-27 (21) is 21 spaces away from 0.

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21 is the answer to your question.

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3 years ago
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Which of the following are valid probability distributions?
Anvisha [2.4K]

Answer:

Step-by-step explanation:

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3 years ago
AB is tangent to the circle k(O) at B, and AD is a secant, which goes through center O. Point O is between A and D∈k(O). Find m∠
drek231 [11]

Answer:

∠BAD=20°20'

∠ADB=34°90'

Step-by-step explanation:

AB is tangent to the circle k(O), then AB⊥BO. If the measure of arc BD is 110°20', then central angle ∠BOD=110°20'.

Consider isosceles triangle BOD (BO=OD=radius of the circle). Angles adjacent to the base BD are equal, so ∠DBO=∠BDO. The sum of all triangle's angles is 180°, thus

∠BOD+∠BDO+∠DBO=180°

∠BDO+∠DBO=180°-110°20'=69°80'

∠BDO=∠DBO=34°90'

So ∠ADB=34°90'

Angles BOD and BOA are supplementary (add up to 180°), so

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In right triangle ABO,

∠ABO+∠BOA+∠OAB=180°

90°+69°80'+∠OAB=180°

∠OAB=180°-90°-69°80'

∠OAB=20°20'

So, ∠BAD=20°20'

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3 years ago
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Please help me on this problem
mr_godi [17]
2(n+7) =3n

n = 14

<span>n = 14</span>
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3 years ago
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