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Anettt [7]
3 years ago
8

Which size bag of cat food shown in the table has the lowest unit price?

Mathematics
1 answer:
garik1379 [7]3 years ago
7 0
Size 40 is the cheapest, because the formula to find lowest price of unit is dividing the price by the unit. so 5.49/24≈ 0.23, 8.00/40=0.2, 15.99/64≈ 0.25
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in complete sentences, explain the process in which this equation would be solved. “Mr Crenshaw can grade one set of papers in 1
hammer [34]

Answer:

6 minutes

Step-by-step explanation:

Mr Crenshaw checks at a rate of 1/10 and Mr. Aguirre checks at a rate of 1/15.

If they work together, they will be checking at a combined rate of:

1/10 + 1/15 = [3(1) + 2(1)]/30

= 5/30 = 1/6

Their combined rate is 1/6 which means they check one set in 6 minutes

3 0
3 years ago
A house that costs $125,400 appreciates at a rate of 3% each year. What is the value of the
ser-zykov [4K]

Answer:

The value after three years is $137,027.97

Step-by-step explanation:

Here, we want to get the value of the home after 3 years

Generally, we have the exponential formula as follows;

y = P(1 + r)^t

where P is the original cost which is $124,400

r is the rate of increase which is 3% = 3/100 = 0.03

t is the time which is 3 years

Substituting these values;

y = 125400(1 + 0.03)^3 = $137,027.97

6 0
3 years ago
Will mark brainliest​
yaroslaw [1]

Answer:

34 is it

Step-by-step explanation:

3 0
3 years ago
Duncan shares 20 percent of all of his his sales commissions with his personal assistant. If Duncan earns x dollars in commissio
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The correct equation that models for this problem is x over y or x/y.
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5 0
3 years ago
Read 2 more answers
Find the differential coefficient of <br><img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%281%2BLnx%29" id="TexFormula1" title="e^
Gemiola [76]

Answer:

\rm \displaystyle y' =   2 {e}^{2x}   +    \frac{1}{x}  {e}^{2x}  + 2 \ln(x) {e}^{2x}

Step-by-step explanation:

we would like to figure out the differential coefficient of e^{2x}(1+\ln(x))

remember that,

the differential coefficient of a function y is what is now called its derivative y', therefore let,

\displaystyle y =  {e}^{2x}  \cdot (1 +   \ln(x) )

to do so distribute:

\displaystyle y =  {e}^{2x}  +   \ln(x)  \cdot  {e}^{2x}

take derivative in both sides which yields:

\displaystyle y' =  \frac{d}{dx} ( {e}^{2x}  +   \ln(x)  \cdot  {e}^{2x} )

by sum derivation rule we acquire:

\rm \displaystyle y' =  \frac{d}{dx}  {e}^{2x}  +  \frac{d}{dx}   \ln(x)  \cdot  {e}^{2x}

Part-A: differentiating $e^{2x}$

\displaystyle \frac{d}{dx}  {e}^{2x}

the rule of composite function derivation is given by:

\rm\displaystyle  \frac{d}{dx} f(g(x)) =  \frac{d}{dg} f(g(x)) \times  \frac{d}{dx} g(x)

so let g(x) [2x] be u and transform it:

\displaystyle \frac{d}{du}  {e}^{u}  \cdot \frac{d}{dx} 2x

differentiate:

\displaystyle   {e}^{u}  \cdot 2

substitute back:

\displaystyle    \boxed{2{e}^{2x}  }

Part-B: differentiating ln(x)•e^2x

Product rule of differentiating is given by:

\displaystyle  \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)

let

  • f(x) \implies   \ln(x)
  • g(x) \implies    {e}^{2x}

substitute

\rm\displaystyle  \frac{d}{dx}  \ln(x)  \cdot  {e}^{2x}  =  \frac{d}{dx}( \ln(x) ) {e}^{2x}  +  \ln(x) \frac{d}{dx}  {e}^{2x}

differentiate:

\rm\displaystyle  \frac{d}{dx}  \ln(x)  \cdot  {e}^{2x}  =   \boxed{\frac{1}{x} {e}^{2x}  +  2\ln(x)  {e}^{2x} }

Final part:

substitute what we got:

\rm \displaystyle y' =   \boxed{2 {e}^{2x}   +    \frac{1}{x}  {e}^{2x}  + 2 \ln(x) {e}^{2x} }

and we're done!

6 0
3 years ago
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