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san4es73 [151]
3 years ago
15

Need help with this one

Mathematics
1 answer:
oee [108]3 years ago
4 0

Answer:

I think it is the last one

Step-by-step explanatio

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(–2) + 6 + 1 = 1 + 6 + (–2) what property is this
jeka94
(–2) + 6 + 1 = 1 + 6 + (–2) is B.Commutative Property
8 0
3 years ago
Read 2 more answers
-3x - 3y = 3 <br> y= -5x - 17
Kruka [31]

you first plug (substitute) in y

-3x - 3(-5x-17)=3

then distribute

-3x+15x+51=3

now combine like terms

12x+51=3

subtract to get 12x by itself

12x=3-51 or 12x=-48

lastly divide by 12 to find x

12x/12=-48/12

x=-4

now find y by plugging x into the other equation

y=-5(-4)-17

y=3

(-4,3)

4 0
3 years ago
There are 25 kids in a class room , five kids are sitting at a desk and the rest are at a table what is the ratio of kids at a d
Misha Larkins [42]

Answer:

5:25 ; 1:5

Step-by-step explanation:

there's 5/25 at a table. replace the slash with a colon.

5:25. Then simplify, getting 1:5

3 0
3 years ago
What is the equation in point-slope form for the line parallel to y = 4x – 14 that contains P(–2, –6)?
lord [1]
Point t slope form:
y + y value = m (x + x value) where m is the gradient
Parallel line must have the same gradient as the two lines never meet, so the gradient must be 4. This eliminates option B and D.
Remember that point-slope form is still an equation, so the values of both sides must be equal. So let's substitute the given coordinates.
Option A:
y-6=4(x+2)
-6-6 (-12) does not equal to 4(-2+2) (0)
Option C:
y+6=4(-2+2)
-6+6 (0) = 4(-2+2) (0)
Therefore, option C is your answer.
8 0
3 years ago
Read 2 more answers
Find the obtuse angle between the following pair of straight lines.
ioda

Given:

y=-2

y=\sqrt{3}x-1

To find:

The obtuse angle between the given pair of straight lines.

Solution:

The slope intercept form of a line is

y=mx+b     ...(i)

where, m is slope and b is y-intercept.

The given equations are

y=0x-2

y=\sqrt{3}x-1

On comparing these equations with (i), we get

m_1=0

m_2=\sqrt{3}

Angle between two lines whose slopes are m_1\text{ and }m_2 is

\tan \theta=\left|\dfrac{m_2-m_1}{1+m_1m_2}\right|

Putting m_1=0 and m_2=\sqrt{3}, we get

\tan \theta=\left|\dfrac{\sqrt{3}-0}{1+(0)(\sqrt{3})}\right|

\tan \theta=\left|\dfrac{\sqrt{3}}{1+0}\right|

\tan \theta=\pm \sqrt{3}

Now,

\tan \theta= \sqrt{3} and \tan \theta=-\sqrt{3}

\tan \theta= \tan 60^\circ and \tan \theta=\tan (180^\circ-60^\circ)

\theta= 60^\circ and \theta=120^\circ

120>90, so it is an obtuse angle and 60, so it is an acute angle.

Therefore, the obtuse angle between the given pair of straight lines is 120°.

6 0
3 years ago
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