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jenyasd209 [6]
4 years ago
13

Hi ...

Mathematics
2 answers:
Makovka662 [10]4 years ago
5 0
To add integers with different signs, keep the sign of the number with the largest absolute value and subtract the smallest absolute value from the largest. Subtract an integer by adding its opposite.
lidiya [134]4 years ago
3 0

Answer:

Its just like normal addition and subtraction just more hard

Step-by-step explanation:

Look it up

You might be interested in
Line MN passes through points M(4, 3) and N(7, 12). If the equation of the line is written in slope-intercept form, y = mx + b,
nataly862011 [7]

Answer:

b = -9.

Step-by-step explanation:

The line passes through (4, 3) and (7, 12). First, we need to find the slope: the rise over the run.

(12 - 3) / (7 - 4) = 9 / 3 = 3.

Now that we have the slope, we can say that m = 3. So, we have an equation of y = 3x + b. To find b, we can use M(4, 3) and say that y = 3 and x = 4.

3 = 3 * 4 + b

b + 12 = 3

b = -9.

Hope this helps!

4 0
3 years ago
Read 2 more answers
Take a look at the picture below and follow the rules using the STRATEGY, you need to draw the strategy to get the answer. brain
Aliun [14]

I would say (I am abbreviating square root to sqrt)

1. 4 sqrt(8488) = 4 sqrt(2x2x2122) = 8 sqrt(2122)

2. 3 sqrt(6936) = 3 sqrt(6x34x34) = 102 sqrt (6)

3. 2 sqrt(8648) = 2 sqrt(2x2x2162) = 4 sqrt(2162)

3 0
3 years ago
I need help on this question anyone please help
Bond [772]

Answer: B.

Step-by-step explanation:

the sum of 5 x 10 with exponent 4 would be 50,000.

multiply that by 12 and it would be 600,000, which is also equal to

6 x 10 with exponent 5.

hope this helps :)

4 0
3 years ago
A shopkeeper buys two types of tea one at $20 for 10 kg and the other at $23 for 10 kg. He mixes the two types and the mixture i
lorasvet [3.4K]
Let us take the case of first type of tea
Cost of 10 kg of tea one = $20
Then
Cost of 1 kg of tea one = (20/10) dollars
                                     = 2 dollars
Now let us take the case of the second kind of tea
Cost of 10 kg of tea = $23
Then
Cost of 1 kg of tea = (23/10) dollars
                               = 2.3 dollars
So
The mixture of 1 kg of tea one
and 1 kg of second type of tea will cost = (2.0 + 2.3) dollars
                                                                = 4.3 dollars
Then the cost of 2kg mixture of tea costs = 4.3 dollars
So
The cost of 10 kg mixture will cost = (4.3/2) * 10 dollars
                                                         = 4.3 * 5 dollars
                                                        = 21.5 dollars
Then
The amount of profit made by selling 10 kg tea at $38 = (38 - 21.5) dollars
                                                                                       = 16.5 dollars
So
Percentage of profit made = (16.5/21.5) * 100
                                           = 1650/21.5
                                           = 76.74 percent
So the percentage of profit made is 76.74%.
3 0
3 years ago
Solve for x<br> (x/r)+(x/w)+(x/t)= 1
MissTica

<em>x</em>/<em>r</em> + <em>x</em>/<em>w</em> + <em>x</em>/<em>t</em> = 1

<em>x</em> (1/<em>r</em> + 1/<em>w</em> + 1/<em>t</em>) = 1

<em>x</em> = 1 / (1/<em>r</em> + 1/<em>w</em> + 1/<em>t</em>)

To make the solution a bit cleaner, multiply through the numerator and denominator by the LCM of each fraction's denominator, <em>rwt</em> :

<em>x</em> = 1 / (1/<em>r</em> + 1/<em>w</em> + 1/<em>t</em>) • <em>rwt</em> / <em>rwt</em>

<em>x</em> = <em>rwt</em> / (<em>rwt</em>/<em>r</em> + <em>rwt</em>/<em>w</em> + <em>rwt</em>/<em>t</em>)

<em>x</em> = <em>rwt</em> / (<em>wt</em> + <em>rt</em> + <em>rw</em>)

5 0
4 years ago
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