<h2><em>we can write (3x^2-5y^2) as (3x-5y)^2</em></h2><h2><em>(
3
x
−
5
y
)
2 as (
3
x−
5
y
)
(
3
x−
5
y
)</em></h2><h2><em>3
x
(
3
x
−
5
y
)
−
5
y
(
3x
−5
y
)</em></h2><h2><em>3
x
(
3
x
−
5
y
)
−
5
y
(3
x
−
5
y
)</em></h2><h2><em>3
x
(
3
x
)
+
3
x
(
−
5y
)
−
5
y
(
3
x
)
−
5
y(
-5
y
)</em></h2><h2><em>9
x
2
−
15
x
y
−
15y
x
+
25
y
2
</em></h2><h2><em> Subtract 15
y
x from −
15
x
y
.</em></h2><h2><em>9
x
2
−
30
xy
+
25
y
2</em></h2><h2><em> HOPE IT HELPS(◕‿◕✿) </em></h2><h2><em> SMILE!! </em></h2>

Synthetic division is used since the equation is of the third degree. The divisors of -3 are 1, -1, 3, +3. So:
| 2 -7 8 -3
<u>1 | 2 -5 3</u>
| 2 -5 3 0
<u> 1 | 2 -3 </u>
2 -3 0
So the factorization is (x-1)² (2x-3)=0. So:


Synthetic division is used since the equation is of the third degree. The divisors of -4 are 1, -1, 2, -2, 4, -4. So:
| 1 -1 0 -4
<u>2 | 2 2 </u>
1 2 2 0
So the factorization is (x-2)(x²+x+2)=0 . When calculating the discriminant of the trinomial, it is concluded that it has no roots since the result is negative. So you only have one solution.


Synthetic division is used since the equation is of the third degree. The divisors of 2 are 1, -1, 2, -2. So:
| 6 7 9 2
<u>-2 | -12 10 -2</u>
6 -5 1 0
So the factorization is (x+2)(6x²-5x+1)=0 . The quadratic equation is solved by the general formula:


Answer:
dividend
Step-by-step explanation:
The DIVIDEND is the original number, which is being divided by the divisor:
QUOTIENT
------------------------
DIVISOR ) DIVIDEND
Answer:
the things wont load whats the question?
Step-by-step explanation:
Yes, it is fairly reasonable... if you round it..
however, if you want exact calculations, then it might not be so reasonable, because it will go over the total amount
so if you round it, then yes it is fairly reasonable