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Zielflug [23.3K]
3 years ago
9

Help with limits will give brainliest

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
5 0

Step-by-step explanation:

option c is correct....

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The width of a rectangle is 9 in. shorter than its length.
Gnoma [55]
Let the width be called x inches, so the length is x+9 inches (width is 9in shorter than length) and x>0

So the area = w*l = x(x+9)

=> x^2+9x=252
=> x^2+9x-252=0
=> x^2 - 12x + 21x - 252 = 0
=>x(x-12) + 21(x-12) = 0
=> (x-12)(x+21)=0
=> x = 12 or -21
but x>0

=> x = 12 in
=> width = 12 in
=> length = 12+9 = 21 inches

brainliest pls
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Double y, then raise the result to the 10th power
vovangra [49]

Answer:

2y^10

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D to B =180
B to D=180
D to C =19
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