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Anna71 [15]
3 years ago
8

Find the distance of point U(2, 3) from point V(5, 7).​

Mathematics
1 answer:
aalyn [17]3 years ago
5 0

Answer:

5

Step-by-step explanation:

You can draw a point at (5,3) and call it point A.

Connect point A with V and U to get VA = 4 and UA = 3.

You get a right triangle and use pythagoream theroem. The answer is the root of 4^2 + 3^2 which equals to 5.

The answer is 5

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Three times a number, decreased by 8, is the same as twice the number, increased by 15. Find
natima [27]
3x - 8 = 2x + 15
Add 8 to both sides
3x = 2x + 23
Subtract 2x from both sides
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3 years ago
The Davidson family wants to expand its regular patio which currently measures 15 ft by 12 ft they want to expand the length and
Juli2301 [7.4K]

Answer:

L and W +5

Step-by-step explanation:

A1=15*12=180

A2=160+A1=340

340 factors

340,1,2,170,5,..., 20,17

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3 years ago
An 12-ounce bottle of orange juice costs $2.64. What is the cost of the orange juice per ounce?
8_murik_8 [283]

Answer:

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Step-by-step explanation:

3 0
2 years ago
Compare the process of solving |x – 1| + 1 < 15 to that of solving |x – 1| + 1 > 15. Check all of the following you includ
zepelin [54]

The required Comparison of the inequalities are

  • The |x – 1| + 1 > 15 represents the value of x lies between 13<x<15.

The range of values encompassing the region's junction is (-13, 15).

  • If x is more than or equal to 15, then x-11+1>15 indicates the value of x is greater than or equal to 13. None of the regions in the intersection are empty.

<h3>What is inequality?</h3>

When comparing two numbers, an inequality indicates whether one is less than, larger than, or not equal to the other.

We take into account the various variables of the inequality

|x – 1| + 1 > 15

Therefore

|-x-1|+1-1<15-1

|-x-1|-1 <14

13<x<15

The required region lies between the inequality -13 <x< 15.

Simplify the inequality Ix-11+1 > 15 we get,

|x-1|+1 > 15

|x+1| +1-1 >15-1

|x-1| > 14

x> 15  

x<-13

  • If x has a value between -13 and x + 15, then the expression "|x-1|+1+115" is true. The range "(-13, 15)" contains the intersection of the region.
  • If "|x-1|+1>15" then either "x >15" or "x-13" applies to the value of x. This region's intersection is unoccupied.

Read more about inequalities

brainly.com/question/20383699

#SPJ1

7 0
2 years ago
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