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labwork [276]
3 years ago
6

A car rental company offers the following two plans for renting a car:

Mathematics
1 answer:
AveGali [126]3 years ago
3 0

Answer:

181.818181...Miles

Step-by-step explanation:

50 = 30 + 11X

X = 181.81818181...

If you multiply 11 by 181.81 repeting you will get 20 and 30 + 20 = 50

So You would have to go 181.81 repeating miles for it to be equal

If you are rounding up it would be 182 miles to justify choosing plan B

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Multiply the numerators, and then multiply the denominator. Find the product. <br><br> 11/12 x 2/5
ki77a [65]

Hello from MrBillDoesMath!

Answer:

11/30



Discussion:

( 11/12) x (2/5) = (11 * 2)/(12*5)  = 22/60 = 11/30



Regards,  

MrB

6 0
3 years ago
What's the answer to x^2-6x-8?
solong [7]

Answer:

0

Step-by-step explanation:

(x-4)(x-2)=0

If any individual factor on the left side of the equation is equal to 0

the entire expression will be equal to 0

Set the first factor equal to 0 and solve

x=4

The final solution is all the values that make

(x-4)(x-2)=0

x=4,2

6 0
3 years ago
Please help thank you!!
Dmitry [639]

Answer:

<h2>a. V = 420 cm³</h2><h2>b. V = 444 in³</h2><h2>c. V = 108 cm³</h2><h2>d. V = 324 m³</h2>

Step-by-step explanation:

We have the rectangular prisms.

The formula of a volume of a rectangular prism is:

V=lwh

l - length

w - width

h - height

==========================================

Look at the picture.

a.

Two congruent rectangular prisms 14cm × 3cm × 5cm.

V=2(14\cdot3\cdot5)=420\ cm^3

b.

One rectangular prism 15in × 4in × 6in and next 7in × 4in × 3in:

V=15\cdot4\cdot6+7\cdot4\cdot3=360+84=444\ in^3

c.

One rectangular prism 10cm × 3cm × 2cm and next 4cm × 3cm × 4cm:

V=10\cdot3\cdot2+4\cdot3\cdot4=60+48=108\ cm^3

d.

One rectangular prism 10m × 3m × 6m and next 8m × 3m × 6m:

V=10\cdot3\cdot6+8\cdot3\cdot6=180+144=324\ m^3

4 0
3 years ago
Use stokes' theorem to evaluate c f · dr where c is oriented counterclockwise as viewed from above. f(x, y, z = xyi + 5zj + 7yk,
Helga [31]
The intersection can be parameterized by

C:=\mathbf r(t)=\begin{cases}x(t)=6\cos t\\y(t)=6\sin t\\z(t)=5-6\cos t\end{cases}

with 0\le t.

By Stoke's theorem, the integral of \mathbf f(x,y,z)=xy\,\mathbf i+5z\,\mathbf j+7y\,\mathbf k along C is equivalent to

\displaystyle\int_C\mathbf f(x(t),y(t),z(t))\cdot\mathrm d\mathbf r(t)=\iint_S\nabla\times\mathbf f\,\mathrm dS

where S is the region bounded by C. The line integral reduces to

\displaystyle\int_0^{2\pi}(36\sin t\cos t\,\mathbf i+(25-30\cos t)\,\mathbf j+42\sin t\,\mathbf k)\cdot(-6\sin t\,\mathbf i+6\cos t\,\mathbf j+6\sin t\,\mathbf k)\,\mathrm dt
=\displaystyle\int_0^{2\pi}(54(\cos3t-\cos t)-30(3\cos2t-5\cos t+3)+(126-126\cos2t)\,\mathrm dt
=\displaystyle\int_0^{2\pi}(36+96\cos t-216\cos2t+54\cos3t)\,\mathrm dt
=72\pi
4 0
3 years ago
(35 + 5)[16 + (12 divide 4)]
nadezda [96]

Answer:

59

Step-by-step explanation:

8 0
3 years ago
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