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2 years ago

I need a thorough explanation for question 4 please. It’s about Operations of Powers/Exponents.

Mathematics

1 answer:

miskamm [114]2 years ago

3 0

Answer:

goto gauth maths and ask again

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What is the solution to the system of linear equations?<br> 2x+4y=38<br> 10x+3y=105

tamaranim1 [39]

Hello :
<span>2x+4y=38 ...(1)
10x+3y=105....(2)
-10x-20y = - 190
10x+3y =105
add : -17y = - 85
y = 5
subsct in (1) : 2x +20 =38
2x = 18
x=9

</span>

6 0

3 years ago

Read 2 more answers

A chord consists of notes that sound good together. The C major chord starting at middle C has the following frequencies: C - 26

Bingel [31]

Answer:

The frequency of note E is:

f(E) = 330 Hz

The frequency of note C is:

f(C) = 262 Hz

The ratio of the frequency of note E to the frequency of note C is just the quotient of these two frequencies:

r = f(E)/f(C) = 330Hz/262Hz = 330/262 = 1.26

Now, we want to find how man E waves will fit in the length of four C waves.

Note that here the word "length" is used, so we need to work with the wavelengths, not with the frequencies.

For waves, we have the relationship:

v = f*λ

where:

v = velocity (in this case, velocity of the sound = 343 m/s)

f = frequency

λ = wavelength.

So, the length of a single E wave is:

λ(E) = (343 m/s)/(330 1/s) = 1.04 m

And the length of a single C note is:

λ(C) = (343 m/s)/(262 1/s) = 1.30 m

In four C waves, the length is:

4*λ(C) = 4*1.30m = 5.2m

The number of E waves that fit in the length of four C waves is equal to the quotient between the length of four C waves and one E wave:

N = (4*λ(C))/(λ(E) ) = (5.2 m)/(1.04m) = 5.14

So we can fit 5 E waves into four C waves.

6 0

3 years ago

Darius is putting tiles on the roof of his house. After working for 3 1/3 hours, he has completed 4/5 of the roof. Can Darius pu

tangare [24]

Answer:

No.

Step-by-step explanation:

It is given that Darius is putting tiles on the roof of his house.

Darius had completed = $\frac{4}{5}$ th of the work

He takes time = $3 \frac{1}{3}$ hours to complete $\frac{4}{5}$ th of the work

The remaining work = $1 -\frac{4}{5}$

$=\frac{5-4}{5}$

$=\frac{1}{5}$

∴ Darius completes $\frac{4}{5}$ th of the work in = $\frac{10}{3}$ hours

So, $\frac{1}{5}$ th of the work in = $\frac{10}{3} \times \frac{5}{4} \times \frac{1}{5}$ hours

$=\frac{10}{12}$ hours

Therefore total time taken to complete the work $=\frac{10}{3}+\frac{10}{12}$ hours

$=\frac{40+10}{12}$ hours

$=\frac{50}{12}$ hours

$=4\frac{2}{12}$ hours

$=4\frac{1}{6}$ hours

Thus, Darius continues to work at the same rate will not be able to complete the work in 4 hours.

8 0

3 years ago

What is the percent of change from 50 to 83

Annette [7]

Answer: 66%

Step-by-step explanation: 83- 50 50 x 100% = 66%

5 0

3 years ago

Somebody please help

Gnesinka [82]

What do u need help with

5 0

3 years ago