2-3(z-5)+11=4
<em>Distribute</em>
2-3z+15+11=4
<em>Move the constants to gether but make sure they keep thei signs</em>
2+15+11-3z=4
<em>Simplify</em>
28-3z=4
<em>Start to Isolate the variable by subtracting </em>28<em> from </em><u><em>both</em></u><em> sides of the equation</em>
-3z=-24
<em>Completely isolate the variable by deviding the </em><u><em>whole</em></u><em> equation by </em>-3
z=8
<u><em>If you would like anything explained, just ask</em></u>
Claire at 2/4 of the brownie and 1/6 of the leftover.
<span>z=−13</span> would be your answer
Answer:
Kindly check explanation
Step-by-step explanation:
Given the data :
Technician __Shutdown
Taylor, T___4
Rousche, R _ 3
Hurley, H__ 3
Huang, Hu___2
Gupta, ___ 5
The Numbe of samples of 2 possible from the 5 technicians :
We use combination :
nCr = n! ÷ (n-r)!r!
5C2 = 5!(3!)2!
5C2 = (5*4)/2 = 10
POSSIBLE COMBINATIONS :
TR, TH, THu, TG, RH, RHu, RG , HHu, HG, HuG
Sample means :
TR = (4+3)/2 = 3.5
TH = (4+3)/2 = 3.5
THu = (4+2) = 6/2 = 3
TG = (4 + 5) = 9/2 = 4.5
RH = (3+3) = 6/2 = 3
RHu = (3+2) /2 = 2.5
RG = (3 + 5) = 8/2 = 4
HHu = (3+2) = 2.5
HG = (3+5) = 8/2 = 4
HuG = (2+5) / 2 = 3.5
Mean of sample mean (3.5+3.5+3+4.5+3+2.5+4+2.5+4+3.5) / 10 = 3.4
Population mean :
(4 + 3 + 3 + 2 + 5) / 5 = 17 /5 = 3.4
Population Mean and mean of sample means are the same.
This distribution should be approximately normal.
1000add10000. 11000............
