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zlopas [31]
2 years ago
6

12345678909876543211234567890987654321

Mathematics
2 answers:
sashaice [31]2 years ago
8 0

Answer:

3.579

Step-by-step explanation:

the answer is clearly given in the question

jekas [21]2 years ago
5 0

Answer:

Numbers

Step-by-step explanation:

Free po!nts

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* Which expression is equivalent to 7(p + 5) *​
luda_lava [24]

Answer:

7(p+5)

=7p+35

this two be equivalent since when you expand it's the sama

7 0
2 years ago
25 points for right answers
Free_Kalibri [48]
You divide by 16 so you can get each ingredient per serving then you multiply that by 4 and you get your answer

8 0
2 years ago
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What is 5.23 divided by 9
maks197457 [2]
0.581 i used a calculator
7 0
2 years ago
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3^x= 3*2^x solve this equation​
kompoz [17]

In the equation

3^x = 3\cdot 2^x

divide both sides by 2^x to get

\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3

Take the base-3/2 logarithm of both sides:

\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}

Alternatively, you can divide both sides by 3^x:

\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13

Then take the base-2/3 logarith of both sides to get

\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}

(Both answers are equivalent)

8 0
2 years ago
I need help in everything
elena-s [515]
<span>-6f+13=2f-11
-6f - 2f  = -11 - 13
-8f = -24
   f = 3</span>
4 0
3 years ago
Read 2 more answers
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