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son4ous [18]
3 years ago
8

Jeremy ran 5 yards 2 feet 3 inches. In the same time, John ran 9 yards 1 foot 10 inches. How many inches farther did John run th

an Jeremy
Mathematics
2 answers:
m_a_m_a [10]3 years ago
5 0
5 yards 2 feet 3 inches:
1 yard=36 inches; 5 yards=180 inches
1 foot=12 inches; 2 feet=24 inches
180+24+3=207 inches

9 yards 1 foot 10 inches:
9 yards=324 inches
1 foot=12 inches
324+12+10=346 inches
346-207=139 inches
John ran 139 inches fartheer than Jeremy
adelina 88 [10]3 years ago
4 0
Jeremy: 5 yards, 2 feet, 3 inches
John: 9 yards, 1 foot, 10 inches

You need to find how many inches Jeremy and John ran. There are 36 inches in a yard, so multiply 5 yards by 36.
(5)(36) = 180 inches

There are 12 inches in a foot, so multiply 2 feet by 12.
(2)(12) = 24 inches

Add 180 and 24 inches to 3 inches.
180 + 24 + 3 = 207 inches

Jeremy ran 207 inches.

Now for John:
Multiply 9 yards by 36 inches.
(9)(36) = 324 inches

1 foot = 12 inches

Add 324 and 12 inches to 10 inches.
324 + 12 + 10 = 346 inches

John ran 346 inches.

Subtract Jeremy's run from John's.
346 - 207 = 139 inches

John ran 139 inches farther than Jeremy.
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What is the sum of an infinite geometric series if the first term is 81 and the common ratio is 2⁄3?
Marrrta [24]

C

the sum to infinity of a geometric series  = \frac{a}{1-r}

where a is the first term and r the common ratio

= \frac{81}{\frac{1}{3} } = 81 × 3 = 243



4 0
3 years ago
13. Jimmy is writing a paper for one of his classes. The paper has to be 3,000 words
Kipish [7]

Answer:

500

Step-by-step explanation:

3000 divided by 6

Hope this helped, sorry if I'm wrong!

3 0
3 years ago
Read 2 more answers
Simplify the following? (x^5)^4​
Elis [28]
X^20 i hope this helps
8 0
3 years ago
An engineering scale model shows a church that is 2 inches tall. If the scale is 1 inch = 265 feet, how tall is the actual churc
Nitella [24]
That would be 2 * 265  = 530 feet tall.
4 0
3 years ago
I am confused in these problems ?<br>8. 9.
Liula [17]

Answer:

8. 14

9. 720

Step-by-step explanation:

Both questions are asking you to find the GCD (Greatest Common Divisor) and LCM (Lowest Common Multiple).

8. Find the greatest number that can divide 392 and 462 exactly.

Find the GCD of 392 and 462:

  1. Find the prime factorization of 392

2^3 × 7^2 (2 × 2 × 2 × 7 × 7)

  2. Find the prime factorization of 462

2 × 3 × 7 × 11

  3. To find the GCD, multiply all prime factors common to all numbers  

GCF = 2 × 7, therefore GCD = 14.

9. What is the smallest number that is divisible by 20, 48, and 72?

Find the LCM of 20, 48, and 72:

  1. Find the prime factorization of 20

2^5 (2 × 2 × 5)

  2. Find the prime factorization of 48

2^4 x 3 (2 × 2 × 2 × 2 × 3)

  3. Find the prime factorization of 72

2^3 x 3^2 (2 × 2 × 2 × 3 × 3)

  4. To find the LCM, multiply all prime factors

LCM = 2^4 × 3^2 × 5 (2 × 2 × 2 × 2 × 3 × 3 × 5), therefore GCF = 720

Calculator Input:

The easiest way to find the GCD or LCM of 2 or more numbers is by using a scientific calculator. Input GCD(x,y) or LCM(x,y) for the answer. This will work for any amount of numbers as long as the input is logical.

For questions 8 and 9, you would type in GCD(392,462) and LCM(20,48,72).

Not all calculators are made the same, so other labels might be GCF or HCF instead of GCD, and LCF instead of LCM. I use GCD and LCM because that's how it is on my calculator. There isn't any difference, so using any label is fine.

5 0
2 years ago
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