Unfortunately there isn't enough information.
Check out the diagram below. We have segment BC equal to 120 meters long. Points B, C, D and E are all on the edge of the same circle. According to the inscribed angle theorem, angles BDC and BEC are congruent. This shows that the surveyor could be at points D or E, or the surveyor could be anywhere on the circle. There are infinitely many locations for the surveyor to be at, which leads to infinitely many possible widths of this canal.
The equation to find out the volume in this case is V=x*x*2x, or V=2x^3. Use this we can get that the volumes would be 16, 54, 128, and 250.
A= 3.14* 12^2
= 3.14* 144
= 452.16cm^2
Answer:
m∠ABD = 20°
Step-by-step explanation:
The bisector makes angles ABD and BDC congruent, so ...
7x -1 = 4x +8
3x = 9 . . . . . . add 1-4x to both sides
x = 3
m∠ABD = (7x-1)° = (7·3 -1)°
m∠ABD = 20°
Hope this helps you out.... 85x + 26y <span>
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