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VMariaS [17]
3 years ago
14

N. -2x - 40 = 8(1 -x)​

Mathematics
1 answer:
Irina-Kira [14]3 years ago
4 0

Answer:

x=8

Step-by-step explanation:

−2x−40=8(1−x)

Step 1: Simplify both sides of the equation.

−2x−40=8(1−x)

−2x+−40=(8)(1)+(8)(−x)(Distribute)

−2x+−40=8+−8x

−2x−40=−8x+8

Step 2: Add 8x to both sides.

−2x−40+8x=−8x+8+8x

6x−40=8

Step 3: Add 40 to both sides.

6x−40+40=8+40

6x=48

Step 4: Divide both sides by 6.

\frac{6x}{6} =\frac{48}{6}

to get the answer

x=8

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In 1988, a certain model of car cost $17000. What would be the cost of that car in 2017 dollars?
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Answer:

$66,092.50

Step-by-step explanation:

In 1988, the car cost $17,000

Annual inflation over this period was 3.54% from 1988 to 2017

After adjusted for inflation, $17,000.00 in 1978 is equal to $66,092.50 in 2017

Therefore, the cost of that car in 2017 is closest to $66,092.50

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How many seconds are in two weeks?
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Answer:

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Step-by-step explanation:

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Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

5 0
3 years ago
In ΔCDE, \overline{CE}
abruzzese [7]

Answer:

m\angle CDE=14^o

Step-by-step explanation:

we know that

An exterior angle of a triangle is equal to the sum of the opposite interior angles.

see the attached figure to better understand the problem

so

∠DEF=∠ECD+∠CDE

substitute the given values

(4x+5)^o=(x+9)^o+(x+8)^o

solve for x

Combine like terms

(4x+5)^o=(2x+17)^o

Group terms

4x-2x=17-5

2x=12

x=6

Find the measure of angle CDE

m\angle CDE=(x+8)^o

substitute the value of x

m\angle CDE=(6+8)=14^o

8 0
3 years ago
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