What is the first step in writing f(x) = 6x2 + 5 – 42x in vertex form?
2 answers:
Answer:
Option 3rd is correct
Write the function in standard form.
Step-by-step explanation:
The standard form of the quadratic equation is given by:
As per the statement:
Given the function:
We have to find the first step writing f(x) vertex form.
Firstly, write the given function in standard form
by definition we have;
Therefore, the first step writing f(x) vertex form is, Write the function in standard form.
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The problem can be solved step by step, if we know certain basic rules of summation. Following rules assume summation limits are identical.
Armed with the above rules, we can split up the summation into simple terms:
=> (a) f(x)=28n-n^2
=> f'(x)=28-2n
=> at f'(x)=0 => x=14
Since f''(x)=-2 <0 therefore f(14) is a maximum
(b) f(x) is a maximum when n=14
(c) the maximum value of f(x) is f(14)=196
Armed with the above rules, we can split up the summation into simple terms:
=> (a) f(x)=28n-n^2
=> f'(x)=28-2n
=> at f'(x)=0 => x=14
Since f''(x)=-2 <0 therefore f(14) is a maximum
(b) f(x) is a maximum when n=14
(c) the maximum value of f(x) is f(14)=196