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zheka24 [161]
3 years ago
16

What is the first step in writing f(x) = 6x2 + 5 – 42x in vertex form?

Mathematics
2 answers:
Marat540 [252]3 years ago
7 0
F(x) = 6x² + 5 - 42x

first step in writing the f(x) in vertex form? WRITE THE FUNCTION IN STANDARD FORM.

f(x) = 6x² - 42x + 5

Exponents must be in decreasing order. 
Rom4ik [11]3 years ago
7 0

Answer:

Option 3rd is correct

Write the function in standard form.

Step-by-step explanation:

The standard form of the quadratic equation is given by:

y=Ax^2+Bx+C

As per the statement:

Given the function:

f(x) = 6x^2+5-42x

We have to find the first step writing f(x) vertex form.

Firstly, write the given function in standard form

by definition we have;

f(x) = 6x^2-42x+5

Therefore, the first step writing f(x) vertex form is, Write the function in standard form.

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The graph of a polynomial S(x) = (2x - 3)(x – 4)(x+3) has x-intercepts at 3.x values.
dezoksy [38]

Answer:

Step-by-step explanation:

x-intercepts exist where y is equal to 0. Where y is equal to 0 is where the graph goes through the x-axis. Our x-intercepts are (2x-3), (x + 3), and (x-4). Again, since x-intercepts exist where y = 0, then by the Zero Product Property, 2x - 3 = 0, x - 4 = 0, and x + 3 = 0. In the first x-intercept:

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