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3 years ago

how high a hill would a 75 kg hiker has to climb to increase her gravitational potential energy by 10000 j

Physics

2 answers:

ikadub [295]3 years ago

7 0

Your answer would be 13.6 m

riadik2000 [5.3K]3 years ago

3 0

Answer:

$13.60 \ m$

Explanation:

Given that,

Mass of the hiker is 75 kg

The gravitational potential energy by 10000 J

To solve :

The height of the hill.

Solve :

The gravitational potential energy of object , $G=10000\ J$ .

Also, Mass of hiker, $m=75 \ kg.$

Now,

The relation between Gravitational potential energy (G) and Mass of object (M) is given as:

$G=m\times g \times h.$

Where , g is acceleration due to gravity, $g=9.8\ m/s^2.$ .

Putting , values of G, g and m in above equation.

We get, $10000=75\times 9.8 \times h\\\\h=\dfrac{10000}{75\times 9.8} \ m\\\\h=13.60\ m$

Hence , this is the required solution.

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PtichkaEL [24]

Answer:

2.5 km/30min

Explanation:

Divide 5 by 2 because 30 min is half of 1 hour. when you do that you get 2.5

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2 years ago

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sashaice [31]

Answer:

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Explanation:

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8 0

3 years ago

Un motor realiza un trabajo de 5000 j en 20 s a) ¿ cual es la potencia del motor ?B)¿en cuanto tiempo desarollan el mismo trabaj

zimovet [89]

Answer:

a. Potencia = 250 Watts

b. Tiempo = 333.33 segundos

Explanation:

Dados los siguientes datos;

Energía = 5000 Joules

Tiempo = 20 segundos.

Para encontrar el poder;

Poder = energía/tiempo

Potencia = 5000/20

Potencia = 250 Watts

B. ¿Para saber cuánto tarda una máquina en realizar el mismo trabajo;

Dado: potencia = 15 W

Tiempo = energía/poder

Tiempo = 5000/15

Tiempo = 333.33 segundos

3 0

3 years ago

A small rocket with mass 20.0 kg is moving in free fall toward the earth. Air resistance can be neglected. When the rocket is 80

Mekhanik [1.2K]

Answer:

= 308.5 N

Explanation:

acceleration of rocket for safe landing

$v_{y} ^{2} = v_{0} ^{2} +2ay$

$a = \frac{v_{y}^{2} - v_{0}^{2} }{2y}$

$v_{0}$ = initial velocity

$v_{y}$ =final Velocity

m = mass of rocket

$\frac{0^{2} - 30^{2} }{2\times80}$

-5.625 $m/s^{2}$

Upward force

F - mg = ma

F = ma+ mg

F = m(a+g)

m= mass

a = 5.625 $m/s^{2}$

g = 9.8 $m/s^{2}$

= 20(5.625 $m/s^{2}$ + 9.8 $m/s^{2}$ )

= 308.5 N

7 0

3 years ago