Answer:

Acceleration, in m/s, of such a rock fragment = 
Explanation:
According to Newton's Third Equation of motion

Where:
is the final velocity
is the initial velocity
a is the acceleration
s is the distance
In our case:

So Equation will become:

Acceleration, in m/s, of such a rock fragment = 
Answer:
Mariah trained for months leading up to the marathon and won. Her sole motivation was that after seeing her winning the marathon, her friends and family would call her as motivated and athletic. It means that Mariah wanted to fulfill her esteem needs.
Explanation:
<u>According to Abraham Maslow:</u>
Safety needs includes the personal security, the safety of health, resources and property. etc.
Physiological needs falls at the lowest level of basic needs. It includes food, water, rest. etc which are necessary for an individual's survival.
Esteem includes the need of respect and self-confidence.
Cognitive needs includes the desire of knowledge, to know things, to know what is happening and why is it happening around you.
<u>In Mariah's case</u><u>, she needed respect and motivation and thus she was trying to fulfill her esteem needs by winning the marathon.</u>
<u />
Answer:
a. 
b. 
c. 
Explanation:
First, look at the picture to understand the problem before to solve it.
a. d1 = 1.1 mm
Here, the point is located inside the cilinder, just between the wire and the inner layer of the conductor. Therefore, we only consider the wire's current to calculate the magnetic field as follows:
To solve the equations we have to convert all units to those of the international system. (mm→m)

μ0 is the constant of proportionality
μ0=4πX10^-7 N*s2/c^2
b. d2=3.6 mm
Here, the point is located in the surface of the cilinder. Therefore, we have to consider the current density of the conductor to calculate the magnetic field as follows:
J: current density
c: outer radius
b: inner radius
The cilinder's current is negative, as it goes on opposite direction than the wire's current.




c. d3=7.4 mm
Here, the point is located out of the cilinder. Therefore, we have to consider both, the conductor's current and the wire's current as follows:

As we see, the magnitud of the magnetic field is greater inside the conductor, because of the density of current and the material's nature.
Answer:We have , a relation in frequency f and wavelength λ of a wave having the velocity v as ,
v=fλ ,
given f=60Hz , λ=20m ,
therefore velocity of wave , v=60×20=1200m/s
Answer:
B) grams
The SI unit for mass is grams.