the density of gold is 19.3 g/cm3. suppose a certain gold wedding ring deplaced 0.55mL of liquid when dropped in a glass of spar
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The acorn was at a height of <u>4.15 m</u> from the ground before it drops.
The acorn takes a time t to fall through a distance h₁, which is the length of the scale. When the acorn reaches the top of the scale, its velocity is u.
Calculate the speed of the acorn at the top of the scale, using the equation of motion,
Since the acorn falls freely under gravity, its acceleration is equal to the acceleration due to gravity g.
Substitute 2.27 m for s (=h₁), 0.301 s for t and 9.8 m/s² for a (=g).
If the acorn starts from rest and reaches a speed of 6.067 m/s at the top of the scale, it would have fallen a distance h₂ to achieve this speed.
Use the equation of motion,
Substitute 6.067 m/s for v, 0 m/s for u, 9.8 m/s² for a (=g) and h₂ for s.
The height h above the ground at which the acorn was is given by,
The acorn was at a height <u>4.15m</u> from the ground before dropping down.
Answer:
intensity of sound at level of microphone is 0.00139 W / m 2
sound intensity level at position of micro phone is 91.456 dB
EXPLANATION:
Given data:
power of sound P = 31 W
distance betwen microphone & speaker is 42 m
a) intensity of sound at microphone is calculated as
= 0.00139 W / m 2
b) sound intensity level at position of micro phone is
where I_o id reference sound intensity and taken as
= 91.456 dB