Distance is the total length covered = 2m + 3m = 5m
Displacement is his distance from original position.
Displacement = 2m + (-3)m. Representing the 3m walked back as -3.
Displacement = 2m - 3m = -1m.
So his displacement is 1m behind his original starting point.
Answer:
346.70015 m/s
Explanation:
In the x axis speed is
![v_x=149\ m/s](https://tex.z-dn.net/?f=v_x%3D149%5C%20m%2Fs)
In the y axis
![v_y=\sqrt{2gh}\\\Rightarrow v_y=\sqrt{2\times 9.8\times 5000}](https://tex.z-dn.net/?f=v_y%3D%5Csqrt%7B2gh%7D%5C%5C%5CRightarrow%20v_y%3D%5Csqrt%7B2%5Ctimes%209.8%5Ctimes%205000%7D)
The resultant velocity is given by
![v=\sqrt{v_x^2+v_y^2}\\\Rightarrow v=\sqrt{149^2+2\times 9.8\times 5000}\\\Rightarrow v=346.70015\ m/s](https://tex.z-dn.net/?f=v%3D%5Csqrt%7Bv_x%5E2%2Bv_y%5E2%7D%5C%5C%5CRightarrow%20v%3D%5Csqrt%7B149%5E2%2B2%5Ctimes%209.8%5Ctimes%205000%7D%5C%5C%5CRightarrow%20v%3D346.70015%5C%20m%2Fs)
The magnitude of the overall velocity of the hamper at the instant it strikes the surface of the ocean is 346.70015 m/s
The amplitude is from the absolute value of the 0 point on the y-axis to the highest(peak) or lowest(troph) point of the wave. In this question, 3cm is the highest and -3cm is the lowest, so the amplitude is 3cm.
Answer:
Potential energy of spring = 24 Joules.
Explanation:
Given the following data;
Spring constant = 85N/m
Extension, e = 0.75m
Mass = 25kg
To find the potential energy of a spring
Potential energy of a spring is given by the formula;
P.E = ½ke²
Substituting into the equation, we have
P.E = ½*85*0.75²
P.E = 42.5 * 0.5625
P.E = 23.91 ≈ 24 Joules
P.E = 24 Joules