All categories

1 year ago

If themass is 50kg, what weight of water is to be displaced to float on water? why

Physics

1 answer:

ludmilkaskok [199]1 year ago

5 0

Answer:if youre looking for the weight of the thermas in genral it should be 500n

Explanation:using the formula w=mg

w=500x10

giving us 500 newtons which is the weight.

You might be interested in

Tarzans mass is 75kg. calculate his weight

monitta

Answer:

75kg=165.346697lbs

Explanation: F A T

6 0

3 years ago

If the Sun suddenly turned off, we would not know it until its light stopped coming. How long would that be, given that the Sun

Yuliya22 [10]

Answer:

8.33 minutes

Explanation:

First let us find out how much time it takes for the light for the sun to reach the earth

Distance between Earth and Sun is 1.5×10¹¹ m

Speed of light = 3×10⁸ m/s

$\text{Time taken}=\frac{1.5\times 10^{11}}{3\times 10^8}\\\Rightarrow \text{Time taken}=500\ seconds$

Converting to minutes

$500\ seconds=\frac{500}{60}=8.33\ minutes$

So, it takes 8.33 minutes for the light from the sun to reach Earth.

This means that we would be receiving light for 8.33 minutes after the Sun turned off.

3 0

3 years ago

What is the relationship between temperature, dew point temperature, and air pressure

olchik [2.2K]

Dew point is the temperature at which the water vapor in the air condenses , then evaporates. The barometric or air pressure is independent from the dew point.

6 0

2 years ago

3) A driver in a 1000-kg car traveling at 24 m/s slams on the brakes and skids to a stop. If the coefticient of friction between

Natali5045456 [20]

Answer:

A) 37 m

Explanation:

The car is moving of uniformly accelerated motion, so the distance it covers can be calculated by using the following SUVAT equation:

$v^2 -u^2 = 2ad$ (1)

where

v = 0 m/s is the final velocity of the car

u = 24 m/s is the initial velocity

a is the acceleration

d is the length of the skid

We need to find the acceleration first. We know that the force responsible for the (de)celeration is the force of friction, so:

$F=ma=-\mu mg$

where

m = 1000 kg is the mass of the car

$\mu = 0.80$ is the coefficient of friction

a is the deceleration of the car

g = 9.8 m/s^2 is the acceleration due to gravity

The negative sign is due to the fact that the force of friction is against the motion of the car, so the sign of the acceleration will be negative because the car is slowing down. From this equation, we find:

$a=-\mu g$

And we can substitute it into eq.(1) to find d:

$v^2 -u^2 = 2(\-mu g) d\\d= \frac{v^2-u^2}{-2 \mu g}=\frac{0-(24 m/s)^2}{-2(0.80)(9.8 m/s^2)}=36.7 m \sim 37 m$

7 0

3 years ago

Which of the following describes electric change?

DedPeter [7]

It would be B, like charges repel and unlike charges attract.

8 0

3 years ago

Read 2 more answers