Given:
ABCD is a quadrilateral
AC = 12, DE = 4 and FB = 5
To find:
The area of the polygon.
Solution:
AC bisects the quadrilateral into two triangles.
Area of triangle:
<u>Area of triangle DAC:</u>
Area of triangle DAC = 24 square units.
<u>Area of triangle BAC:</u>
Area of triangle BAC = 30 square units.
Area of polygon = Area of triangle DAC + Area of triangle BAC
= 24 square units + 30 square units
= 54 square units
The area of the polygon is 54 square units.
The x =0 and y = 1 are coordinates of point E, which partitions the directed line segment from A to B into a ratio of 1:2.
<h2>We have to determine</h2>
What are the x- and y- coordinates of point E, which partitions the directed line segment from A to B into a ratio of 1:2?
<h3>According to the question</h3>A line segment at points A(2, -3) and B (-4, 9).
The x- and y- coordinates of point E, which partitions the directed line segment from A to B into a ratio of 1:2 is given by;
Where
Substitute all the values in the formula;
Hence, the x =0 and y = 1 are coordinates of point E, which partitions the directed line segment from A to B into a ratio of 1:2.
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