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2 years ago

9

A school assembly had 25 students in attendance, and 20% of them were first-graders. How many first-graders were at the assembly

?

1 answer:

artcher [175]2 years ago

5 0

Answer:

5

Step-by-step explanation:

20%=0.2

25 x 0.2 = 5

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F(x) = 3x-1 and g(x)=2x^2

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Answer:

See below

Step-by-step explanation:

a. here you are to multiply the two functions together:

$(3x-1)(2x^{2} )=6x^{3}-2x^{2}$

b. here you are to subtract g from f:

$(3x-1)-(2x^{2})=-2x^{2}+3x-1$

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$3(2x^{2} )-1=6x^{2} -1$

d. here you are compose f into g. In other words, pick up the whole f function and plug it into g wherever you see an x:

$2(3x-1)^2$

You now have to FOIL out the (3x-1) like so:

$2[(3x-1)(3x-1)]$

which gives you

$2(9x^{2} -6x+1)$

Distribute in the 2 and you'll end up with the answer:

$18x^{2} -12x+2$

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3 years ago

PLEASE HELP WITH THESE 4 QUESTIONS IF CORRECT ILL MARK BRAINLIEST

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Step-by-step explanation:

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The fish population of Lake Collins is decreasing at a rate of 5% per year. In 2004 there were about 1,350 fish. Write an expone

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Answer:

Part 1) The exponential function is equal to $y=1,350(0.95)^{x}$

Part 2) The population in 2010 was $992\ fish$

Step-by-step explanation:

Part 1) Write an exponential decay function that models this situation

we know that

In this problem we have a exponential function of the form

$y=a(b)^{x}$

where

y ----> the fish population of Lake Collins since 2004

x ----> the time in years

a is the initial value

b is the base

we have

$a=1,350\ fish$

$b=(100\%-5\%)=95\%=0.95$

substitute

$y=1,350(0.95)^{x}$ ----> exponential function that represent this scenario

Part 2) Find the population in 2010

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$y=1,350(0.95)^{x}$

so

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substitute

$y=1,350(0.95)^{6}=992\ fish$

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3 years ago