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11Alexandr11 [23.1K]
2 years ago
6

Show three ways to write the expression 5 times x algebraically.

Mathematics
2 answers:
adoni [48]2 years ago
5 0
<h2>Answer:</h2>

<h3>d + 5</h3>

<h2>Step-by-step explanation:</h2>

<h3>Remember that d is just an unknown number." 5 more than " means add 5 </h3><h3>onto a number 8 is " 5 more than 3 " 20 </h3><h3>is 5 more than 15. " 5 more than d is " d + 5</h3>

<h3>Hope its help </h3>

<h3>#Carry On Learning</h3>
Dahasolnce [82]2 years ago
4 0

Step-by-step explanation:

1st way: 5x

2nd way: 5.x

third way: 5(x)

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51450÷98 can u show me how
Andreas93 [3]

51450 divided by 98
is 525 with remainder 0


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7 0
3 years ago
Marsha counted 24 birds at the wildlife refuge, and Aamir counted 86 birds. What is the ratio of Aamir’s Burge to Marshall’s bir
vaieri [72.5K]

Answer:

43:12

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
Suppose Mahkah makes a Native American lunch in a pot that is shaped like a right cylinder. If
Harman [31]

The pot can hold 5.23 quarts

Step-by-step explanation:

  • Step 1: Find the volume of the right cylinder shaped pot.

Diameter of the pot = 8 in

⇒ Radius = 4 in

Height = 6 in

⇒ Volume of the pot = πr²h = 3.14 × 4² × 6

                                   = 301.44 in³

  • Step 2: Convert inches to quarts.

1 in³ = 0.017316 liquid quarts

⇒ 301.44 in³ = 301.44 × 0.017316 = 5.23 quarts

6 0
3 years ago
A museum requires a minimum number of chaperones proportional to the number of students on a field trip. The museum requires a m
Stells [14]

Answer: See explanation

Step-by-step explanation:

Here is the complete question:

A museum requires a minimum number of chaperones proportional to the number of students on a field trip. The museum requires a minimum of 3 chaperones for a field trip with 24 students. Which of the following could be combinations of values for the students and the minimum number of chaperones the museum requires? Choose 2 answers.

A. Students: 72

Minimum of chaperones: 9

B. Students: 16

Minimum of chaperones: 2

C. Students: 60

Minimum of chaperones: 6

D. Students: 45

Minimum of chaperones: 5

E. Students: 40

Minimum of chaperones: 8

Since the museum requires a minimum of 3 chaperones for a field trip with 24 students. This means that there will be 24/3 = 8 students per chaperone.

We then divide the number of students given in the question by the number of chaperone to know our answers. This. Will be:

Students: 72

Minimum of chaperones: 9

This will be: 72/9 = 8

Therefore, this is correct.

B. Students: 16

Minimum of chaperones: 2

This will be: 16/2 = 8

This is correct

C. Students: 60

Minimum of chaperones: 6

This will be: = 60/6 = 10.

Therefore, this is wrong

D. Students: 45

Minimum of chaperones: 5

This will be 45/5 = 9

Therefore, this is wrong.

E. Students: 40

Minimum of chaperones: 8

This will be: 40/5 = 8.

Therefore, this is wrong.

Therefore, options A and B are correct.

3 0
3 years ago
Read 2 more answers
William and Debra Pierce are celebrating their 20th anniversary by having a reception at a local reception hall. They have budge
erica [24]

The greatest number of people that William and Debra may invite and still stay within their budget is 63.

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Since William and Debra have budgeted $2,500 for their reception. Therefore, their total expenses should be equal to the total expenses in the reception.

Budget = Total expenses

Budget = Reception hall Cleanup charge + $38 per person fee

Let the number of people invited to the party be represented by x,

$2,500 = $100 + $38(x)

2500 = 100 + 38x

2500 - 100 = 38x

2400 = 38x

x = 2400 / 38

x = 63.157 ≈ 63

Hence, the greatest number of people that William and Debra may invite and still stay within their budget is 63.

Learn more about Equation here:

brainly.com/question/14686792

#SPJ1

5 0
2 years ago
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