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irga5000 [103]
3 years ago
9

Solve the formula Ax + By = C for y.

Mathematics
2 answers:
Illusion [34]3 years ago
8 0
Ax + By = C
-ax            -ax
-------------------
By  = -Ax + C
---     ------------
B             B
--------------------
y = -Ax + C
      ----------
            B
Sveta_85 [38]3 years ago
7 0

Answer: y=C+Ax/B

Step-by-step explanation:

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I need help proving this ASAP
Ket [755]

Answer:

See explanation

Step-by-step explanation:

We want to show that:

\tan(x +  \frac{3\pi}{2} )  =  -   \cot \: x

One way is to use the basic double angle formula:

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{ \sin(x)  \cos( \frac{3\pi}{2} )  +   \cos(x)  \sin( \frac{3\pi}{2}) }{\cos(x)  \cos( \frac{3\pi}{2} )   -    \sin(x)  \sin( \frac{3\pi}{2}) }

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{ \sin(x) ( 0)  +   \cos(x) (  - 1) }{\cos(x) (0)   -    \sin(x) (  - 1) }

We simplify further to get:

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{ 0  -   \cos(x) }{0 +    \sin(x) }

We simplify again to get;

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{- \cos(x) }{ \sin(x) }

This finally gives:

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  -  \cot(x)

6 0
4 years ago
Are these right triangles ?<br> Answer please ASAP
V125BC [204]

Answer: Yes.

Step-by-step explanation: Right triangles are 90° and with a square. This is a right triangle. Just remove the line that makes it a triangle, you'll see.

4 0
3 years ago
Find an equation for the line perpendicular to y = − 1 /9 x + 4 with x-intercept at x = -1
prisoha [69]
Y = (-1/9).x + 4
The slope m of the line perpendicular to y = (-1/9).x + 4 is equal to 9:
(if the product of 2 slopes = - 1, then the 2 lines are perpendicular)

y = 9x + b, Since it passes by the point (-1,0) , then:
 0= 9(-1) + b and b = 9
Final equation:

y = 9x+9
 
6 0
3 years ago
The crew on a fishing boat caught 4 fish that weighed a total of 1,092 pound. The tarpon weighed twice as much as the amberjack
Savatey [412]

ddddd

Let T be the weight of Tarpon

Let A be the weight of amberjack

Let W be the weight of white marlin

Let TU be the weight of Tuna

The crew on a fishing boat caught 4 fish that weighed a total of 1,092 pound.

Total weight = 1092

T + A + W + TU = 1092

The tarpon weighed twice as much as the amberjack

T= 2 A

  the white marlin weighed twice as much as the tarpon.

W = 2 T

We know T is 2A  so W = 2(2A) = 4 A, W = 4A

The weight of the tuna was 5 times the weight of the Amber jack.

TU = 5A

T = 2A  , W = 4A , TU = 5A

Replace it in our equation

T + A + W + TU = 1092

2A + A + 4A + 5A = 1092

12A = 1092

Divide both sides by 12

A = 91

the weight of amberjack = 91 pounds

the weight of white marlin = 4A = 4(91) = 364 pounds

the weight of Tarpon = 2A = 2(91) = 182 pounds

the weight of Tuna= 5A = 5(91)=455 pounds

7 0
3 years ago
URGENT! (Please give the correct answer!)
OlgaM077 [116]

By taking x as subject the formula becomes x = (v² - u²)/2a.

<h3>What is Equation?</h3>

An equation is a mathematical statement with an 'equal to=' symbol between two expressions that have equal values.

Here given equation:

      v² = u² + 2ax

     2ax = v² - u²

      x = (v² - u²)/2a

Thus, by taking x as subject the formula becomes x = (v² - u²)/2a.

Learn more about Equation from:

brainly.com/question/10413253

#SPJ1

5 0
2 years ago
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