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kotegsom [21]
3 years ago
10

You need to have a password with 4 letters followed by 3 even digits between 0 and 9, inclusive. If the characters and digits ca

nnot be used more than once, how many choices do you have for your password?
Mathematics
1 answer:
Gekata [30.6K]3 years ago
4 0

Answer: 21528000 choices

Step-by-step explanation:

Since there are 26 letters of the alphabet and no alphabet is to be used more than once,

then the first letter can be chosen in 26ways

Second letter can be chosen im 25ways

Third letter can be chosen in 24ways

Fourth letter can be chosen in 23ways.

Since we can only use even digits, then the even digits we have are "0,2,4,6,8"

Then the first digit can be chosen in 5ways

Second digit can be chosen in 4ways

Third digit can be chosen in 3ways.

Total number of choices for this pass word = 26×25×24×23×5×4×3 = 21528000 choices

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disa [49]
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8 0
3 years ago
Hexagon DEFGHI is translated on the coordinate plane below to create hexagon D'E'F'G'H'I':
SVETLANKA909090 [29]

Answer:

(x, y)→(x − 8, y − 7)

Step-by-step explanation:

If we take the hexagon DEFGHI coordinates and apply the rule (x, y)→(x − 8, y − 7) we get:

D (2, 5) → (2 - 8, 5 - 7) = (-6, -2) which corresponds to point D'

E (5, 5) → (5 - 8, 5 - 7) = (-3, -2) which corresponds to point E'

F (6, 3) → (6 - 8, 3 - 7) = (-2, -4) which corresponds to point F'

G (5, 1) → (5 - 8, 1 - 7) = (-3, -6) which corresponds to point G'

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6 0
3 years ago
Read 2 more answers
Factorize 2a^2+7a-15​
loris [4]

\huge\bf  \pink {\underline{Solution :-}}

2 {a}^{2}  + 7a - 15

= 2 {a}^{2}  + 10a - 3a - 15

= 2a(a + 5) - 3(a + 5)

= (a + 5)(2a - 3)

\sf \red{Hence, Answer \:  is  \: (a + 5)(2a - 3).}

\\

\bf \purple{ \underline{ Important  \: Formulas  \: for  \: Factorization :-}}

• \:  {a}^{2}  + 2ab + {b}^{2} =  {(a + b)}^{2}

• \: (a + b)(a - b) =  {a}^{2}  -  {b}^{2}

• \:  {a}^{2} - 2 ab  +  {b}^{2}  =  {(a - b)}^{2}

• \:  {a}^{3}  + 3 {a}^{2} b + 3a {b}^{2}  +  {b}^{3} =  {(a + b)}^{3}

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•  \:  {(a + b)}^{2}  +  {(a - b)}^{2}  = 2( {a}^{2}  +  {b}^{2} )

• \: {(a + b)}^{2}   -   {(a - b)}^{2}  = 4ab

• \: (a + b)( {a}^{2}   -ab   +  {b}^{2}  ) =  {a}^{3}  +  {b}^{3}

• \: (a  -  b)( {a}^{2}    + ab   +  {b}^{2}  ) =  {a}^{3}   -  {b}^{3}

• \:   {( \frac{a + b}{2} )}^{2}  - ( {\frac{a - b}{2} } )^{2}  = ab

5 0
3 years ago
Read 2 more answers
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