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3 years ago

10

You need to have a password with 4 letters followed by 3 even digits between 0 and 9, inclusive. If the characters and digits ca

nnot be used more than once, how many choices do you have for your password?

1 answer:

Gekata [30.6K]3 years ago

4 0

Answer: 21528000 choices

Step-by-step explanation:

Since there are 26 letters of the alphabet and no alphabet is to be used more than once,

then the first letter can be chosen in 26ways

Second letter can be chosen im 25ways

Third letter can be chosen in 24ways

Fourth letter can be chosen in 23ways.

Since we can only use even digits, then the even digits we have are "0,2,4,6,8"

Then the first digit can be chosen in 5ways

Second digit can be chosen in 4ways

Third digit can be chosen in 3ways.

Total number of choices for this pass word = 26×25×24×23×5×4×3 = 21528000 choices

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Mean score (μ) = 80

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What is the least common denominator of 3/12 and 3/8 rename each fraction in the pair.

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4 years ago

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Find the solutions to the following linear-quadratic systems algebraically. Select the ordered pair that is one of the correct s

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Answer:

(-2, 6)

Step-by-step explanation:

we have

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$y=2x+10$ ----> equation B

equate equation A and equation B

$x^{2} +3x+8=2x+10$

$x^{2} +3x+8-2x-10=0$

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The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

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$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +x-2=0$

so

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substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(1)(-2)}} {2(1)}$

$x=\frac{-1\pm\sqrt{9}} {2}$

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$x=\frac{-1+3} {2}=1$

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For x=-2

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3 years ago

If P(x) = x^2 + X + 2 and Q(x) = 3x^3 - 2, find P(6).

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Answer:

The answer is P(6) is 44.

Step-by-step explanation:

Given:

If P(x) = x^2 + X + 2 and Q(x) = 3x^3 - 2.

Now, to find P(6).

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Therefore, the answer is P(6) is 44.

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3 years ago