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4 years ago

What is 45 1/2% written as a fraction in simplest form

1 answer:

4 0

<span>45.5% is equivalent to 45.5/100. To remove the decimal from the fraction, multiply both by the same factor of ten so they are integers: 455/1000. This can be cancelled down to 91/200 in its simplest form.</span>

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what is the equation in slope- intercept form of the line that passes through the points (-26 -11) and (39, 34) ?A) y = -9/13 x

Alisiya [41]

what is the equation in slope- intercept form of the line that passes through the points (-26 -11) and (39, 34) ?

A) y = -9/13 x + 7

B) y = -9/13 x - 7

C) y = 9/13 x + 7

D) y = 9/13 x - 7

step 1

Find out the slope

m=(34+11)/(39+26)

m=45/65

simplify

m=9/13

step 2

Find the equation in slope intercept form

y=mx+b

we have

m=9/13

point (39,34)

substitute and solve for b

34=(9/13)(39)+b

b=34-27

b=7

therefore

the equation is

y=(9/13)x+7

<h2>option C</h2>

6 0

2 years ago

A manufacturing company makes two types of water skis, a trick ski and a slalom ski. The relevant manufacturing data are given

asambeis [7]

Answer:A manufacturing company makes two types of water skis, a trick ski and a slalom ski. The relevant manufacturing data are given in the table. (A) If the profit on a trick ski is $40$ and the profit on a slalom ski is $30,$ how many of each type of ski should be manufactured each day to realize a maximum profit? What is the maximum profit? (B) Discuss the effect on the production schedule and the maximum profit if the profit on a slalom ski decreases to $25$ and all other data remains the same. (C) Discuss the effect on the production schedule and the maximum profit if the profit on a slalom ski increases to $45$ and all other data remain the same.

Step-by-step explanation:

6 0

3 years ago

Janie took out a loan for $4850 at a 13.8% APR, compounded monthly, to buy

Masteriza [31]

Answer:

The total payment Janie have to make is $5466 .

Step-by-step explanation:

Given as :

The loan principal = $4850

The rate of interest applied = 13.8% compounded monthly

Let The time period of loan = t years

The monthly payment she make = $455.50 each month

I.e She make payment for t years = $455.50 × n

where n is the number of terms

<u>From Compound Interest</u>

Amount = Principal × $(1+\dfrac{\textrm rate}{12\times 100})^{12\times time}$

Or, $455.50 × n = $4850 × $(1+\dfrac{\textrm 13.8}{12\times 100})^{12\times time}$

Or, $\dfrac{455.50}{4850}$ × n = $(1.0115)^{12\times 1}$

Or, 0.0939 × n = $(1.0115)^{12}$

Or, 0.0939 × n = 1.14707

∴ n = $\dfrac{1.14707}{0.0939}$

I.e n = 12.21 ≈ 12

So, The number of terms Janie she will pay = 12

So, The total payment she have to make = $455.50 × 12 = $5466

Hence The total payment Janie have to make is $5466 . Answer

8 0

3 years ago

Read 2 more answers

Suppose it is known from large amounts of historical data that X, the number of cars that arrive at a specific intersection duri

Andrew [12]

Answer:

a) P(x>8) = 0.3937

b) P(x = 2) =0.04661

Step-by-step explanation:

a) From to find the probabilty that in this specific time period, more than 8 cars arrive at the intesection, we use the probability function thus

P(x>8) = 1 - P(x≤8), Cause you can use the complement for calculate this probability , then:

P(x≤8) = $\frac{e^{-6}*6^{0} }{0!}+\frac{e^{-6}*6^{1} }{1!}+\frac{e^{-6}*6^{2} }{2!}+...$ , until x= 8, then you obtain:

P(x≤8)=0.6063 and

P(x>8) = 1 - P(x≤8)= 1-0.6063 = 0.3937

b) P(x=2)= $\frac{e^{-6}*6^{2} }{2!}$

P(x = 2) =0.04661

3 0

3 years ago

Help with 5 and 6???

abruzzese [7]

$f(x) = x^2 -3x + 4 \ \ \ g(x) = x - 2\\f \circ g(x) = f(g(x)) = (x-2)^2 - 3(x-2) + 4 = x^2 - 4x + 4 - 3x + 6 + 4 = x^2 - 7x + 14\\f \circ g(5) = 5^2 - 7\cdot5 + 14 = 25 - 35 + 14 = 4$

5 0

3 years ago