Answer:
the lower value of the interval = 35.26
Step-by-step explanation:
The mean number is u = 40.1
n = 16
the mean number called x is 38.1
the standard deviation = 5.8
given a 95% Confidence Interval
The lower value of the confidence interval is?
<u>solution</u>
There is a infinite population and the standard deviation of the population is known,
the below formula is used for determining an estimate of the confidence limits of the population mean, i.e.
x ± (
zₐσ)/ √n
For a 95% confidence level, the value of za is taken from the confidence interval table = 1.96.
the confidence limits of the population=
x ± (
zₐσ)/ √n
38.1 ± (1.96*5.8)/ √16
38.1 ± 11.368/4
38.1 ± 2.842
40.942 or 35.258
Thus, the 95% confidence limits are 40.942 or 35.258
this prediction is made with confidence that it will be correct nine five times out of 100.
finally, the lower value of the interval = 35.26
