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kotegsom [21]
3 years ago
12

Ill give u brainliest pls help asap!

Mathematics
1 answer:
Jobisdone [24]3 years ago
7 0
<h3>✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽</h3>

➷ 4  - 0 = 4

The answer is A. $4

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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Plz help me!!!!!!!! Which expressions are equivalent? <br> A.<br> B.<br> C.<br> D.
likoan [24]

Answer:

Option A

Step-by-step explanation:

The answer is Option A because - \frac{2}{3} j + \frac{1}{5}k can be writen as \frac{1}{5}k - \frac{2}{3}j.

6 0
2 years ago
Someone please help me
bearhunter [10]
B. triangle and triangular prism
6 0
3 years ago
How to simplify -3 (4×-5y-5×)
VMariaS [17]
Distribute -3 to the rest of the numbers by multiplying them together. That’s all you need to do you don’t have to solve
6 0
3 years ago
Read 2 more answers
A) The card states that it makes 60 cookies. How much flour is required for 30 people?
ikadub [295]

Answer:

assuming each person gets one cookie

a 1 1/4 C

b 3/8 tsp

Step-by-step explanation:

divide recipe in half

a 2.5/2=1.25

b 3/4 ÷ 2 ; rewrite to 6/8 ÷2 = .375

7 0
3 years ago
If the right side of the equation dy dx = f(x, y) can be expressed as a function of the ratio y/x only, then the equation is sai
melomori [17]

Answer:

 y = x*sqrt(Cx - 1)

Step-by-step explanation:

Given:

                                  dy / dx = (x^2 + 5y^2) / 2xy

Find:

Solve the given ODE by using appropriate substitution.

Solution:

- Rewrite the given ODE:

                               dy/dx = 0.5(x/y) + 2.5(y/x)

- use substitution y = x*v(x)

                               dy/dx = v + x*dv/dx

- Combine the two equations:

                                v + x*dv/dx = 0.5*(1/v) + 2.5*v

                                x*dv/dx = 0.5*(1/v) + 1.5*v

                                x*dv/dx = (v^2 + 1) / 2v

-Separate variables:

                                 (2v.dv / (v^2 + 1) = dx / x  

- Integrate both sides:

                                 Ln (v^2 + 1) = Ln(x) + C

                                 v^2 + 1 = Cx

                                 v = sqrt(Cx - 1)

- Back substitution:

                                (y/x) = sqrt(Cx - 1)

                               y = x*sqrt(Cx - 1)

                         

3 0
3 years ago
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