Which expression is equivalent to 2x^5 + 4x^4 - 5x^5 - (3x^4

Can yall help, whoever answers correctly will get brainllest!

melamori03 [73]

Answer:

A,C,D

Step-by-step explanation:

4 0

3 years ago

Daniel wrote the following two-column proof for the given information.

Pavel [41]

The information given about the proof does that Daniel made an error on line 2.

<h3>How to illustrate the information?</h3>

Given:

1. AB = 3x +2; BC = 4x + 8; AC = 38

2. AB + BC = AC incorrect (not an angle angle addition postulate)

3. 3x+2 + 4x + 8 = 38 correct

4. 7x + 10 = 38 correct

5. 7x = 28 correct

6. x = 4

Daniel made an error on line 2.

Here is the complete question:

Daniel wrote the following two-column proof for the given information. Given: AB = 3x + 2; BC = 4x + 8; AC = 38 Prove: x = 4 Statements Reason 1. AB = 3x + 2; BC = 4x + 8; AC = 38 1. Given 2. AB + BC = AC 2. Angle Addition Postulate 3. 3x + 2 + 4x + 8 = 38 3. Substitution Property of Equality 4. 7x + 10 = 38 4. Combining Like Terms 5. 7x = 28 5. Subtraction Property of Equality 6. x = 4 6. Division Property of Equality On which line, did Daniel make his error? line 2 line 3 line 4 line 5

Learn more about proof on:

brainly.com/question/4134755

#SPJ1

8 0

2 years ago

Part A

SpyIntel [72]

Answer:

110 + 10x ; 40x

4

Step-by-step explanation:

Given that:

For every visit to Arts museum:

Scenario 1:

Parking fee = $15

Admission fee = $25

Total amount for scenario 1:

If number of visits = x

Total cost = $(15 + 25) × number of visits

Total cost : $40x

With membership :

Price of membership = $110 (one time payment)

Parking fee = $10

Admission fee = $0

Let number of visits = x

Total cost :

Membership fee + (parking fee × number of visits)

$110 + ($10 * x)

= 110 + 10x

B) number of visits for which member cost is less than non-member cost :

Member cost = 110 + 10x

Non member cost = 40x

110 + 10x < 40x

10x - 40x < 110

-30x < 110

x > 3.67

Hence x = 4

Number of visits for which member cost is greater than non member cost is 4

4 0

3 years ago

Assume that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true

IgorLugansk [536]

Answer:

(a) 95% confidence interval for the true average porosity of a certain seam is [4.52 , 5.18].

(b) 98% confidence interval for the true average porosity of a another seam is [4.12 , 4.99].

Step-by-step explanation:

We are given that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true standard deviation 0.75.

(a) Also, the average porosity for 20 specimens from the seam was 4.85.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average porosity = 4.85

$\sigma$ = population standard deviation = 0.75

n = sample of specimens = 20

$\mu$ = true average porosity

Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.

So, 95% confidence interval for the true mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $4.85-1.96 \times {\frac{0.75}{\sqrt{20} } }$ , $4.85+1.96 \times {\frac{0.75}{\sqrt{20} } }$ ]

= [4.52 , 5.18]

Therefore, 95% confidence interval for the true average porosity of a certain seam is [4.52 , 5.18].

(b) Now, there is another seam based on 16 specimens with a sample average porosity of 4.56.

The pivotal quantity for 98% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average porosity = 4.56

$\sigma$ = population standard deviation = 0.75

n = sample of specimens = 16

$\mu$ = true average porosity

Here for constructing 98% confidence interval we have used One-sample z test statistics as we know about population standard deviation.

So, 98% confidence interval for the true mean, $\mu$ is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98 {As the critical value of z at 1% level

of significance are -2.3263 & 2.3263}

P(-2.3263 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.3263) = 0.98

P( $-2.3263 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.3263$ ) = 0.98

P( $\bar X-2.3263 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.3263 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X-2.3263 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+2.3263 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $4.56-2.3263 \times {\frac{0.75}{\sqrt{16} } }$ , $4.56+2.3263 \times {\frac{0.75}{\sqrt{16} } }$ ]

= [4.12 , 4.99]

Therefore, 98% confidence interval for the true average porosity of a another seam is [4.12 , 4.99].

7 0

3 years ago

39÷(2+1)-2×(4+1) PLEASE HELP

Elza [17]

Answer:

3

Step-by-step explanation:

39 ÷ (2+1) - 2 × (4+1)

Using BODMAS Rule,

= 39 ÷ 3 - 2 × 5

= 13 - 2 × 5

= 13 - 10

= 3

5 0

3 years ago

Read 2 more answers

Which expression is equivalent to 2x^5 + 4x^4 - 5x^5 - (3x^4 - 8x^5)