All categories

2 years ago

Cardiovascular endurance which is one of the Physical Fitness Component is the ability to

Health

1 answer:

Korvikt [17]2 years ago

8 0

the ability of the heart and lungs to supply oxygen to the body

You might be interested in

Anyone wanna ta lk im booooooooooooored

Anvisha [2.4K]

Answer:

okay

Explanation:

sjsjsnsbsmsmsvsmsbsvsbs

8 0

2 years ago

Read 2 more answers

In classical conditioning, ________ occurs when the conditioned stimulus is no longer paired with the unconditioned stimulus.

eduard

Answer:

Extinction

Explanation:

Extinction is defined as the weakening and in some cases, a total disappearance of a response that is learned. In classical conditioning, extinction occurs when the conditioned stimulus is no longer connected or paired with the unconditioned stimulus. This results to the conditioned response to cease.

6 0

3 years ago

When was soccer introduced to the United States? 1850 1870 1780 1905

Vaselesa [24]

Answer:

Option a) 1850 is the right option

5 0

3 years ago

Which one of the following drinks would be the top choice for potassium content? A. Chocolate milk B. Low-fat milk C. Juice D. W

Anni [7]

Id say that chocolate milk may have the most potassium of them all. Water does not have any nutritional content (though it is still important). Juice overall will vary, milk does have a high amount of potassium but the added chocolate syrup does add some more.

3 0

2 years ago

Read 2 more answers

Differentiate the following functions (i) x(1+x)^3

statuscvo [17]

Answer:

$\displaystyle y' = (1 + x)^2(4x + 1)$

General Formulas and Concepts:

Algebra I

Terms/Coefficients
Functions
Function Notation
Factoring

Calculus

Derivatives

Derivative Notation

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Explanation:

Step 1: Define

Identify

y = x(1 + x)³

Step 2: Differentiate

Product Rule [Derivative Rule - Chain Rule]: $\displaystyle y' = \frac{d}{dx}[x] \cdot (1 + x)^3 + x \cdot \frac{d}{dx}[(1 + x)^3] \cdot \frac{d}{dx}[1 + x]$
Derivative Property [Addition/Subtraction]: $\displaystyle y' = \frac{d}{dx}[x] \cdot (1 + x)^3 + x \cdot \frac{d}{dx}[(1 + x)^3] \cdot (\frac{d}{dx}[1] + \frac{d}{dx}[x])$
Basic Power Rule: $\displaystyle y' = x^{1 - 1} \cdot (1 + x)^3 + x \cdot 3(1 + x)^{3 - 1} \cdot (0 + x^{1 - 1})$
Simplify: $\displaystyle y' = (1 + x)^3 + 3x(1 + x)^2$
Factor: $\displaystyle y' = (1 + x)^2 \bigg[ (1 + x) + 3x \bigg]$
Combine like terms: $\displaystyle y' = (1 + x)^2(4x + 1)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

5 0

3 years ago