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3 years ago

What's is a supplementary angle

Mathematics

2 answers:

alex41 [277]3 years ago

8 0

Either of two Angles whose sum is 180 degrees

Degger [83]3 years ago

6 0

If two angles are supplementary, then the sum of their measures is 180 degrees. In the image attached below, these angles are supplementary because the sum of their measures equals 180°. When two angles are supplementary, we say that one angle is the supplement of the other.

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A line contains the points (8, 9) and (–12, –7). Using point-slope form, write the equation of the line that is parallel to the

navik [9.2K]

The lines have equal gradients;
m $\frac{16}{20} = \frac{4}{5}$

Equation of line 2;
y=mx+c
y= $\frac{4}{5}$ x+c
-15= $\frac{4}{5*(-5)}$ +c
c=-11
y=4/5x-11

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3 years ago

Which of the following functions has a range of all real numbers?

serious [3.7K]

Only the function in C has the range of all real numbers.
Later on, when you will be familiar with more type of functions you will know that when x is on the power range is usually only positive values or negative values if only not shifted, even if shifted it will only add to its range this numbers by which unit it was shifted.
B is shifted parabola. It has the range of {y| -3≤∞}

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3 years ago

Please help with this

julia-pushkina [17]

Answer:

-11

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Heeeeelp Find the distance of AB if A (2, 6) and B (-5, 2).

evablogger [386]

Answer:

let A (2, 6) be (x1, y1)

B (-5, 2) be (x2, y2)

distance AB =√[(x2 - x1)² + (y2 - y1)²]

√[(-7)²+ (-4)²]

√65

7 0

3 years ago

Write the given second order equation as its equivalent system of first order equations. u′′−5u′−4u=1.5sin(3t),u(1)=1,u′(1)=2.5

lakkis [162]

Answer:

hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer: v = 5v + 4u + 1.5sin(3t),

1.5sin(3t)

Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t) where u'(1) = 2.5 u(1) = 1

v represents the "velocity function" i.e v = u'(t)

As v = u'(t)

u' = v

since u' = v

v' = u"

v' = 5u' + 4u + 1.5sin(3t) ( given that u" - 5u' - 4u = 1.5sin(3t) )

= 5v + 4u + 1.5sin(3t) ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt $\left[\begin{array}{ccc}u&\\v&\\\end{array}\right]$ = $\left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]$ $\left[\begin{array}{ccc}u&\\v&\\\end{array}\right]$ + $\left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]$

Given that u(1) = 1 and u'(1) = 2.5

since v = u'

v(1) = 2.5

note: the initial value for the vector valued function is given as

$\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]$ = $\left[\begin{array}{ccc}1\\2.5\\\end{array}\right]$

7 0

3 years ago