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tiny-mole [99]
3 years ago
14

|x-7|+5 is greater than or equal to 3

Mathematics
1 answer:
jonny [76]3 years ago
6 0
\large\begin{array}{l} \textsf{Solve the absolute value inequality:}\\\\ \mathsf{|x-7|+5\ge 3}\\\\ \mathsf{|x-7|\ge 3-5}\\\\ \mathsf{|x-7|\ge -2}\\\\\\ \textsf{Since absolute values always give a non-negative number,}\\\textsf{every real value for x satisfies the inequatily:}\\\\ \textsf{For all }\mathsf{x\in\mathbb{R},}\\\\ \mathsf{|x-7|\ge 0>-2}\\\\\\ \therefore~~\mathsf{|x-7|\ge 2}\\\\ \textsf{regardless of the value of x.} \end{array}


\large\begin{array}{l} \textsf{Solution set: }\mathsf{S=\mathbb{R}.} \end{array}


If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2180151


\large\textsf{I hope this helps. :-)}


Tags: <em>absolute value inequatily solve solution algebra</em>

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A manufacturing company regularly conducts quality control checks at specified periods on the products it manufactures. Historic
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Answer:

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Step-by-step explanation:

The complete question is:

What is the probability that none of the LED light bulbs are​ defective?

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Let the random variable <em>X</em> represent the number of defective LED light bulbs.

The probability of a LED light bulb being defective is, P (X) = <em>p</em> = 0.03.

A random sample of <em>n</em> = 10 LED light bulbs is selected.

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The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 10 and <em>p</em> = 0.03.

The probability mass function of <em>X</em> is:

P(X=x)={10\choose x}(0.03)^{x}(1-0.03)^{10-x};\ x=0,1,2,3...

Compute the probability that none of the LED light bulbs are​ defective as follows:

P(X=0)={10\choose 0}(0.03)^{0}(1-0.03)^{10-0}

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Thus, the probability that none of the LED light bulbs are​ defective is 0.7374.

6 0
3 years ago
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Step-by-step explanation:

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8 0
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Answer:

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Step-by-step explanation:

3 0
3 years ago
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jenyasd209 [6]

Answer:

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Step-by-step explanation:

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