Answer:
4989600 ways
Step-by-step explanation:
From the question,
The word MATHEMATICS can be arranged in n!/(r₁!r₂!r₃!)
⇒ n!/(r₁!r₂!r₃!) ways
Where n = total number of letters, r₁ = number of times M appears r₂ = number of times A appears, r₃ = number of times T appears.
Given: n = 11, r₁ = 2, r₂ = 2, r₃ = 2
Substitute these value into the expression above
11!/(2!2!2!) = (39916800/8) ways
4989600 ways
Hence the number of ways MATHEMATICS can be arranged without duplicate is 4989600 ways
Either a student passes an exam or fails it. that means the percentage of students who pass plus the percentage of students who fail must add to 100%. this also means that if 22% pass, then 78% fail. there are 68 students total and 78% fail so the number of students failing is:
(78/100)(68) = 53.04 which is approximately 53 students.
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Answer:
i dont understand
Step-by-step explanation:
Answer:
6(3+2)
Step-by-step explanation:
Distributive property:
ab + ac = a(b+c)
where a = greatest common factor (GCF)
GCF of each factor
18 = 2×3×3
12 = 2×2×3
GCF of 18 and 12 = 2×3
= 6
Therefore,
18 + 12 = 6(3) + 6(2)
= 6(3+2)
Where,
6 = a
3 = b
2 = c
ab + ac = a(b+c)
4.5(8 - x) + 36 = 102 - 2.5(3x + 24)
36 - 4.5x + 36 = 102 - 7.5x - 60
72 - 4.5x = 42 - 7.5x
-4.5x + 7.5x = 42 - 72
3x = - 30
x = -30/3
x = -10 <===
Hope this helps!