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3 years ago

Andrea claims that any two cross sections of a cylinder that lie on parallel planes are congruent.

Mathematics

1 answer:

Elodia [21]3 years ago

3 0

Answer:

A)No; any two cross sections of a cylinder that lie on planes parallel to the bases of the cylinder are congruent.

Step-by-step explanation: I had to answer it in class and got it right

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Solve the following equations using any method. Show your work and check your

Gemiola [76]

a) The solution for the equation 2x + 16 = 5x + 4 is x=4.

b) The solution for the equation 3x − 5 = 2x + 14 is x=19.

c) The solution for the equation 5x − 5 = x + 15 is x=5.

Step-by-step explanation:

a) The given equation is 2x + 16 = 5x + 4

From the above equation, it can be found that the equation consists of x terms and constant terms.
Therefore, bring all the x terms on one side and the constant terms on other side of the equation.
This gives the simplified form of the equation to solve for x value.

⇒ 16-4 = 5x-2x

⇒ 12 = 3x

⇒ x = 12/3

⇒ x = 4

The solution for the given equation is x=4.

To check, substitute x=4 in the equation :

2(4) + 16 = 5(4) + 4

8+16 = 20+4

24 = 24

Therefore, the solution x=4 satisfies the equation 2x + 16 = 5x + 4

Similarly,

b) The given equation is 3x − 5 = 2x + 14

⇒ 3x-2x = 14+5

⇒ x = 19

The solution for the given equation is x=19.

To check, substitute x=19 in the equation :

3(19) - 5 = 2(19) + 14

57-16 = 38+14

52 = 52

Therefore, the solution x=19 satisfies the equation 3x − 5 = 2x + 14

Similarly,

c) The given equation is 5x − 5 = x + 15

⇒ 5x-x = 15+5

⇒ 4x = 20

⇒ x = 20/4

⇒ x = 5

The solution for the given equation is x=5.

To check, substitute x=5 in the equation :

5(5) - 5 = 5 + 15

25-5 = 20

20 = 20

Therefore, the solution x=5 satisfies the equation 5x − 5 = x + 15

5 0

3 years ago

A selective university advertises that 96% of its bachelor’s degree graduates have, on graduation day, a professional job offer

OLEGan [10]

Answer:

The probability is $P( p < 0.9207) = 0.0012556$

Step-by-step explanation:

From the question we are told

The population proportion is $p = 0.96$

The sample size is $n = 227$

The number of graduate who had job is k = 209

Generally given that the sample size is large enough (i.e n > 30) then the mean of this sampling distribution is

$\mu_x = p = 0.96$

Generally the standard deviation of this sampling distribution is

$\sigma = \sqrt{\frac{p (1 - p )}{n} }$

=> $\sigma = \sqrt{\frac{0.96 (1 - 0.96 )}{227} }$

=> $\sigma = 0.0130$

Generally the sample proportion is mathematically represented as

$\^ p = \frac{k}{n}$

=> $\^ p = \frac{209}{227}$

=> $\^ p = 0.9207$

Generally probability of obtaining a sample proportion as low as or lower than this, if the university’s claim is true, is mathematically represented as

$P( p < 0.9207) = P( \frac{\^ p - p }{\sigma } < \frac{0.9207 - 0.96}{0.0130 } )$