Let the origin of the coordinate system be the position of ship B at noon. Then the distance between the ships as a function of t (in hours) is
.. d = √((30 +23t)² +(17t)²)
.. = √(818t² +1380t +900)
The rate of change of distance with respect to time is
.. d' = (1/2)(2*818*t +1380)/√(818t² +1380t +900)
.. = (818t +690)/√(818t² +1380t +900)
At t=4, this is
.. d' = (818*4 +690)/√(818*16 +1380*4 +900)
.. = 3962/√19508
.. ≈ 28.37 . . . . . knots
The distance between the ships is increasing at about 28.37 knots at 4 pm.
9514 1404 393
Answer:
Step-by-step explanation:
A graphing calculator can quickly show you the boundaries of the feasible region, and can calculate the values of the objective function.
The answer to #11 is: x = 15
The answer to #12 is: x = 5
Answer:Use the given functions to set up and simplify
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e
a
r
.
2009
=
5000
=
4
%
=
0.04
y
e
a
r
=
0.04
y
e
a
r
=
0.04
Step-by-step explanation:
I Think
Stepby-step explanation:
There is one very important exception to the rule that multiplying or dividing an inequality is the same as multiplying or dividing an equation. Whenever you multiply or divide an inequality by a negative number, you must flip the inequality sign.