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lesantik [10]
3 years ago
8

When originally purchased, a vehicle costing $25,200 had an estimated useful life of 8 years and an estimated salvage value of $

2,800. after 4 years of straight-line depreciation, the asset's total estimated useful life was revised from 8 years to 6 years and there was no change in the estimated salvage value. the depreciation expense in year 5 equals:?

Mathematics
1 answer:
hichkok12 [17]3 years ago
7 0
The depreciated value in year 4 is 14,000. In year 5, it is 8,400. The depreciation expense in year 5 is
.. $14,000 -8,400 = $5,600

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Kareem has a collect of dimes and quarters. He can tell that he has more quarters than dimes, and he knows that he has at most $
Mariulka [41]

Answer:

D<Q≤2 Or D<Q Q+D≤2

Step-by-step explanation:

I'm pretty sure this is the answer but it's been a while since I've done system of inequalities. Essentially the value and number of dimes is less than the value and number of quarters. And the value of both is less than or equal to 2 dollars

8 0
3 years ago
Sketch the graph y=-2/3x-1
Marina86 [1]
Here is the graph i looked it up in google idk if it's right but good luck

6 0
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Help please Math Geometry
Mrac [35]

It's the parallelogram. Therefore

ML = JK, JM = KL, m∠L = m∠J, m∠M = m∠K and m∠M + m∠L = 180°.

ML = 21 → JK = 21

JM = 29 → KL = 29

m∠L = 127° → m∠J = 127°

m∠M + m∠L = 180° → m∠M + 127° = 180° → m∠M = 53°

m∠M = 53° → m∠K = 53°

8 0
3 years ago
The base of a solid oblique pyramid is an equilateral triangle with an edge length of s units.
Assoli18 [71]

Answer:

Option B is correct.i.e.,

Step-by-step explanation:

Given: Pyramid with equilateral triangle as base

           Length of side of equilateral triangle = s unit

to find: height of equilateral triangle

Here we use a property of equilateral triangle.

Perpendicular from a vertex on a side and median of that side of a triangle is same in equilateral triangle.

All heights are of equal length. So, we just need to find one height or length of 1 altitude.

Figure of base triangle is attached

In Δ ABC

AB = BC = AC = s unit

AD is height

BD = \frac{BC}{2}\:=\:\frac{s}{2}\:units

Now, In Δ ABD

using pythagoras theorem

BD² + AD² = AB²

(\frac{s}{2})^2+AD^2=s^2

\frac{s^2}{4}+AD^2=s^2

AD^2=s^2-\frac{s^2}{4}

AD^2=\frac{4s^2-s^2}{4}

AD^2=\frac{3s^2}{4}

AD=\sqrt{\frac{3s^2}{4}}

AD=\frac{\sqrt{3}s}{2}

AD=\frac{s}{2}\sqrt{3}

Therefore, Option B is correct.i.e., \frac{s}{2}\sqrt{3}

4 0
2 years ago
Read 2 more answers
In one month Miranda earned $800 at her part-time job, and $70 was withheld for federal income tax. Suppose she earns $1200 next
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The answer is 105 dollars

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