When originally purchased, a vehicle costing $25,200 had an estimated useful life of 8 years and an estimated salvage value of $
2,800. after 4 years of straight-line depreciation, the asset's total estimated useful life was revised from 8 years to 6 years and there was no change in the estimated salvage value. the depreciation expense in year 5 equals:?
1 answer:
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Answer:
<h3>1) 5(7
first box: 5 * 7 = 35
35 x^2
second box: 5 * -1 = -5
-5x
third box: 5 * 8 = 40
40
answer: 35 - 5x + 40
<h3>2) 2x(4x^2 + 3x + 6)</h3>
first box: 2x * 4x^2
2 * 4 = 8
x * x^2 = x^3
8x^3
second box: 2x * 3x
2 * 3 = 6
x * x = x^2
6x^2
third box: 2x * 6
2 * 6 = 12
12x
answer: 8x^3 + 6x^2 + 12x
<h3>3) (tp + 5)(4p - 6)</h3>
top left box: tp * 4p
p * p = p^2
4t
top right box: tp * - 6
-6tp
bottom left box: 5 * 4p
5 * 4 = 20
20p
bottom right box: 5 * - 6
5 * -6 = -11
-11
answer: 4tp^2 - 6tp + 20p - 11
<h3>4) (4a - 8)(8a - 1)</h3>
top left box: 4a * 8a
4 * 8 = 32
a * a = a^2
32a^2
top right box: 4a * -1
4 * -1 = -4
-4a
bottom left box: -8 * 8a
-8 * 8 = -64
-64a
bottom right box: -8 * - 1
-8 * - 1 = 8
8
32a^2 - 4a - 64a + 8
<em>combine like terms</em>
32a^2 - 68a + 8 = answer
Answer:
Profit function: P(x) = -0.5x^2 + 40x - 300
profit of $50: x = 10 and x = 70
NOT possible to make a profit of $2,500, because maximum profit is $500
Step-by-step explanation:
(Assuming the correct revenue function is 90x−0.5x^2)
The cost function is given by:
And the revenue function is given by:
The profit function is given by the revenue minus the cost, so we have:
To find the points where the profit is $50, we use P(x) = 50 and then find the values of x:
Using Bhaskara's formula, we have:
So the values of x that give a profit of $50 are x = 10 and x = 70
To find if it's possible to make a profit of $2,500, we need to find the maximum profit, that is, the maximum of the function P(x).
The maximum value of P(x) is in the vertex. The x-coordinate of the vertex is given by:
Using this value of x, we can find the maximum profit:
The maximum profit is $500, so it is NOT possible to make a profit of $2,500.
Answer:
-2
Step-by-step explanation:
In the picture
