Answer:
the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.
Step-by-step explanation:
From the given question.
Let p be the length of the of the printed material
Let q be the width of the of the printed material
Therefore pq = 2400 cm ²
q = 
To find the dimensions of the poster; we have:
the length of the poster to be p+30 and the width to be 
The area of the printed material can now be: 
=
Let differentiate with respect to p; we have

Also;

For the smallest area 


p² = 3600
p =√3600
p = 60
Since p = 60 ; replace p = 60 in the expression q =
to solve for q;
q =
q = 
q = 40
Thus; the printed material has the length of 60 cm and the width of 40cm
the length of the poster = p+30 = 60 +30 = 90 cm
the width of the poster =
=
= 40 + 20 = 60
Hence; the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.
Answer:
12 1/2 or 12.5
Step-by-step explanation:
all you have to do is multiply 15 times 5/6
Answer:
That's very simple 2^–1 is equal to 1/2 and 5^0 is equal to 1. Then add this two. 1/2+1 is equal to 1.5.
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To find z, you have to divide -3 and 10, which you would get an odd number. That will be your answer for z :)
Answer:
BC ≈ 14.5 cm
Step-by-step explanation:
Using the sine ratio in the right triangle
sin65° =
=
=
( multiply both sides by 16 )
16 × sin65° = BC , then
BC ≈ 14.5 cm ( to the nearest tenth )