Answer:
There is an 8.22% probability that a randomly selected person has a birthday in November.
Step-by-step explanation:
The theoretical method to find the probability is the division of the number of desired outcomes by the number of total outcomes.
A randomly selected person has a birthday in November
There are 365 days in a year, so the number of total outcomes is 365.
There are 30 days in november, so the number of desired outcomes is 30.
So the probability is
There is an 8.22% probability that a randomly selected person has a birthday in November.
It looks as if "B" is the right angle so
AC is the hypotenuse
AB and BC are the legs
We can write this as:-
P(x) = + x^3 - 5x^2 - 25x + 125
There are 2 changes of real sign so by Descartes Rule of signs there are either 2 positive real roots or 0 positive roots.
P(-x) = - x^3 - 5x^2 + 25x + 125
There is just one change of sign so there is exactly 1 real negative root.
125 is a multiple of 5 so By rational root theorem 5 could be a positive root.
P(5) = 125 - 125 - 125 + 125 = 0 so one zero is 5
if we divide the polynomial by (x - 5) we get the quadratic
x^2 - 25
(x + 5)(x - 5) = 0
x = 5,-5
so the roots are 5 (multiplicity 2) and -5.
2 real positive zeroes and one real negative zero
Answer:
8/45
Step-by-step explanation:
1x8 is 8 and 5x9 is 45
