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2 years ago

An bond forms when one atom gives up one or more electrons to another atom

Chemistry

1 answer:

Vika [28.1K]2 years ago

8 0

This is true i can give you an example if you want

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A pure gold bar is made up of only particles. A.nickel B.copper C.god D.gold

Minchanka [31]

Answer: gold

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3 years ago

Do hydrogen lose 1 2 or 3 electrons to other atoms

iren2701 [21]

Answer: Hydrogen can lose as much as possible there is no limits to it.

Hope this helps!

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Extras: Hydrogen is the chemical element with the symbol H and atomic number 1. hydrogen is the lightest element in the periodic table. Hydrogen is the most abundant chemical substance in the Universe (;

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3 years ago

Give all possible ml values for orbitals that have each of the following: (a) l = 3;

Angelina_Jolie [31]

At l = 3, ml =+3,+2,+1,0,-1,-2,-3

What are quantum numbers?

Quantum numbers are used to describe where around a nucleus a particular electron can be found.
In any given atom, each electron can be described by four quantum numbers.
These are n,l,m1,ms
The values that each number can be are based on a set of rules.

What is a magnetic quantum number ?

It describes the orientation of the orbitals.
It is represented as ml.
The value of this quantum number ranges from (-l to +l).
When l = 2, the value of will be -2, -1, 0, +1, +2.

To know more about magnetic quantum numbers, refer:

brainly.com/question/14650566

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8 0

1 year ago

Helppp nowww plsss!!!

Bond [772]

Pan 4: theyre the smallest and most broken down :)

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3 years ago

The enthalpy of solution (∆H) of KOH is -57.6 kJ/mol. If 3.66 g KOH is dissolved in enough water to make a 150.0 mL solution, wh

Wewaii [24]

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

The enthalpy of solution of KOH is -57.6 kJ/mol. We can calculate the heat released by the solution (Qr) of 3.66 g of KOH considering that the molar mass of KOH is 56.11 g/mol.

$3.66g \times \frac{1mol}{56.11g} \times \frac{(-57.6kJ)}{mol} = -3.76 kJ$

According to the law of conservation of energy, the sum of the heat released by the solution of KOH (Qr) and the heat absorbed by the solution (Qa) is zero.

$Qr+Qa = 0\\\\Qa = -Qr = 3.76 kJ$

150.0 mL of solution with a density of 1.02 g/mL were prepared. The mass (m) of the solution is:

$150.0 mL \times \frac{1.02g}{mL} = 153 g$

Given the specific heat capacity of the solution (c) is 4.184 J/g･°C, we can calculate the change in the temperature (ΔT) of the solution using the following expression.

$Qa = c \times m \times \Delta T\\\\\Delta T = \frac{Qa}{c \times m} = \frac{3.76 \times 10^{3}J }{\frac{4.184J}{g.\° C } \times 153g} = 5.87 \° C$

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

Learn more: brainly.com/question/4400908

7 0

2 years ago