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Assoli18 [71]
3 years ago
7

Write 2 paragraphs on how perfluorocarbon affects scuba divers and their bloodstream.

Chemistry
1 answer:
harina [27]3 years ago
6 0
Not sure (this might to be helpful)
tip: do some research and make it yourself or
tip 2: find 2 paragraphs and change the words (cheating) although don’t really recommend it but there are websites that change the wording for you
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A solution contains one or more of the following ions: Ag+, Ca2+, and Co2+. Lithium bromide is added to the solution and no prec
olchik [2.2K]
<h3>Answer:</h3>

#1. Ca²⁺

# 2. Ca²⁺(aq) + SO₃²⁻(aq) → CaSO₄(s)

#3. 3Ag⁺(aq) + PO₄³⁻(aq) → Ag₃PO₄(s)

<h3>Explanation:</h3>

The question above concerns solubility of salts or ions in water.

The solution given contains Ag+, Ca2+, and Co2+ ions.

  • In the first case, when Lithium bromide is added to the solution, there is no white precipitate formed.
  • In the second case, the addition of Lithium sulfate results in the formation of a precipitate because of the Ca²⁺ in the solution combined with the SO₃²⁻ from lithium sulfate to form an insoluble CaSO₄.
  • The net ionic equation for the reaction is;

Ca²⁺(aq) + SO₃²⁻(aq) → CaSO₄(s)

  • From the solubility rules, all sulfates are soluble except BaSO₄, CaSO₄, and PbSO₄.
  • In the third case, the addition of Lithium phosphate results in the formation of a precipitate because Ag⁺ ions in the solution combine with phosphate ions ( PO₄³⁻) from lithium phosphate to form an insoluble salt, Ag₃PO₄.
  • The net ionic equation for the reaction is;

3Ag⁺(aq) + PO₄³⁻(aq) → Ag₃PO₄(s)

  • According to solubility rules, all phosphates are insoluble in water except Na₃PO₄, K₃PO₄, and (NH₄)₃PO₄.
6 0
3 years ago
Express the quantity 556.2 x 10^-12 in each units<br> A.) ms<br> B.) ns<br> C.) ps<br> D.) fs
zavuch27 [327]
The answer:
we should know the meaning of each abbreviation:
ms means  millisecond, its value is 10^-3 s 
ns means  means  nanosecond,   its value is 10^-9 s
ps means  picosecond, its value is 10^-12 s
fs means  femtosecond, its value is 1x 10^15 s

<span>Expressions of the quantity 556.2 x 10^-12 are</span>
556.2 x 10^-12 =556.2 ps
556.2 x 10^-12 =556.2 x 10^-9 x 10^-3= 556.2 x 10^-9 ms
556.2 x 10^-12 = 556.2 x 10^-3 x 10^-9 = 556.2 x 10^-3 ns
556.2 x 10^-12 = 556.2 x 10^- 27 x 10^15 = 556.2 x 10^- 27 fs
6 0
3 years ago
This is a science question for k12
bixtya [17]

Height of wave - amplitude

Higher the pitch - higher the frequency

Louder - higher the amplitude

bottom of the wave - trough

distance from crest to crest - wave length

top of the wave - crest

6 0
3 years ago
Read 2 more answers
A bomb calorimetric experiment was run to determine the enthalpy of combustion of ethanol. The reaction is The bomb had a heat c
gulaghasi [49]

Answer:

The enthalpy of combustion of ethanol in kJ/mol is -1419.58  kJ/mol.

Explanation:

The heat absorbed by the bomb and water is equal to the product of the heat  capacity and the temperature change. Working with this equation, and assuming no heat is lost to  the surroundings, we write :

qcal= Ccal × ΔT= 490 J/K × 276.7 K= <u>135,583 J</u> = 135.58 kJ

Note we expressed the temperature change in K, because the heat capacity is written in K.

<u> Now that we have the heat of combustion, we need to calculate the molar heat.  </u>

Because qsystem = qrxn + qcal and qrxn = -qcal, the heat change of the reaction is -135.58 kJ.

This is the heat released by the combustion of 4.40 g of ethanol ; therefore, we can write  the <u>conversion factor as 135.58 kJ/ 4.40 g</u>.

The molar mass of ethanol is 46.07 g, so the heat of combustion of 1 mole of ethanol is :

molar heat of combustion= -135.58 kJ/4.40 g x 46.07 g/ 1 mol= -1419.58 kJ/mol

Therefore, the enthalpy of combustion of ethanol in kJ/mol is -1419.58  kJ/mol.

3 0
3 years ago
G8_SCIENCE_BSA_21_22
S_A_V [24]

Answer:

Explanation: Over the course of a year, areas near Earth’s equator receive more direct energy from the Sun than areas near Earth’s poles.  Which of the following correctly describes one result of this heating pattern?


8 0
3 years ago
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