All categories

2 years ago

The diagrams may not be drawn to scale. Find the value of y. AC is a straight line. А 56° yº B 123° су

Mathematics

1 answer:

Sliva [168]2 years ago

3 0

<h3><u>Answer:</u></h3>

The answer is y = 67°.

<h3><u>Step-by-step explanation:</u></h3>

56 + y + (180 - 123) = 180
=> 56 + y + 57 = 180
=> y = 180 - 113
=> y = 67°

<h3><u>Conclusion:</u></h3>

Therefore, the answer is y = 67°.

Hoped this helped.

$-BrainiacUser1357-$

You might be interested in

Abby's friend told her that he drew a quadrilateral with exactly one pair of parallel sides. Abby said it must be a trapezoid. I

Ratling [72]

Answer:

Yes, she is correct

Step-by-step explanation:

A trapezoid has exactly one pair of parallel lines and 4 sides

8 0

2 years ago

Read 2 more answers

An interior designer sketches a design for a rectangular rug. The dimensions of a sketch are 4 inches by 7.5 in. The dimensions

Black_prince [1.1K]

3,000 in.

(4 x 10) + (7.5 x 10) = 3000

The dimensions on the sketch are 10 times less than the actual rug.

40 in., 7.5 in.

The drawing lengths are ten times more, so you just multiply the dimensions by 10, and then multiply the product you find out to find the actual area of the rug.

4 0

3 years ago

Membership in an art club is expected to grow by about 4% per month. Currently, there are 350 members in the club. In about how

igomit [66]

500=350(1+0.04/12)^12x
Solve for x
500/350=(1+0.04/12)^12x
X=(Log(500/350)/log(1+0.04/12))/12
X=9 months

6 0

3 years ago

Read 2 more answers

Divided the following rational expressions<br> t^3-t^2-2t/t-5 divided by t^2-t-2

butalik [34]

t³-t²-2t/t -5 )/(t²-t-2)

(t^4-t^3-7t)/t^3-t^2-2t)

(t³-t²-7)/(t²-t-2)

I hope that's help !

7 0

3 years ago

A 90 percent confidence interval for the slope of a regression line is determined to be (-0.181, 1.529). Which of the following

GenaCL600 [577]

Answer: a. The correlation coefficient of the data is positive.

Step-by-step explanation:

Estimated slope of sample regression line = $\dfrac{Upper \ limit + lower\ limit}{2}$

Here , confidence interval : (-0.181, 1.529)

Estimated slope of sample regression line = $\dfrac{-0.181+1.529}{2}$

$=\dfrac{1.348}{2}\\\\=0.674\ \ \ \ [\text{ positive}]$

⇒Correlation coefficient(r) must be positive, So a. is true.

But, d. and e. are wrong(0.674 ≠ 0 or 1.348).

We cannot check residuals or its sum from confidence interval of slope of a regression line, so b is wrong.

We cannot say that scatterplot is linear as we cannot determine it from interval, so c. is wrong

So, the correct option : a. The correlation coefficient of the data is positive.

7 0

3 years ago