3 years ago

Identify the turning point of the function f(x)= x^2 -2x + 8 by writing its equation in vertex form . show work

1 answer:

7 0

The turning point of a parabola is its vertex.

$f(x)=x^2-2x+8\\
f(x)=x^2-2x+1+7\\
f(x)=(x-1)^2+7$
The vertex is $(1,7)$

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Given:

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Midpoint of EC:

The midpoint of EC can be determined using the formula,

$Midpoint=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

Substituting the coordinates E(2t,0) and C(2p, 2r), we get;

$Midpoint=(\frac{2t+2p}{2},\frac{0+2r}{2})$

Simplifying, we get;

$Midpoint=(\frac{2(t+p)}{2},\frac{2r}{2})$

Dividing, we get;

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