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Dahasolnce [82]
3 years ago
15

How many stops does Mia make on her drive? Explain

Mathematics
1 answer:
Sati [7]3 years ago
3 0

Can you provide a picture or what is going on in the picture and or text?

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What is the slope of the line that passes through the points (7.-12) and (-9,36)?​
REY [17]

Answer:

Step-by-step explanation:

m = slope where

m = rise / run

rise = y2 - y1  

run = x2 - x1

where  

the given point P1 = (7, -12)

and is in the form of (x1,y1)  

and

the given point P2 = (-9,36)  

is  in   the   form  of   (x2,y2)

then

m =  ( y2 - y1 ) / ( x2 - x1 )

m = ( 36 - (-12) ) / ( -9 -7 )

m = ( 36 + 12 ) /  ( - 16 )

m =  48 /  - 16

m = - 3

the slope is negative 3

slope = - 3

4 0
3 years ago
Sandy grew 8 turnips joan grew 6 turnips how many turnips did they grow in all
kumpel [21]
8 turnips + 6 turnips = 14 turnips together
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3 years ago
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Salvatori charges $9 Per hour for babysitting Kendra chargers $8.50 per hour if they both work for 6 hours How much more money w
andreev551 [17]
54 dollars would be earned
8 0
3 years ago
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What value is equivalent to 52 + 53 − 54? A) -475 B) -350 C) -125 D) 5
Dafna1 [17]

None of these answer choices are correct. The answer would be 51. 52+53=105

105-54=51

7 0
3 years ago
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How to solve logarithmic equations as such
Serga [27]

\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5

\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}

5 0
3 years ago
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