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2 years ago

I am not able to solve this question

Mathematics

2 answers:

Alexxx [7]2 years ago

5 0

Answer:

Step-by-step explanation:

join my stream for an explanation

(ChildofHermes)

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im only streaming for 15 more hours

adelina 88 [10]2 years ago

5 0

Answer:

Choice C

Step-by-step explanation:

2654^0 and 5^0

Which is greater?

There's a law of exponents for solving this type of question.

The law states that,

x^0 = 1

Same case here.

2654^0
1

And,

Hence, they are same.

2654⁰ = 5⁰

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If he starts at 1 and jumps 3 units to the right, then where is he on the number line? How far away from zero is he?

Ilya [14]

Answer:

If you mean he starts at 1 on the Y axis (vertical line), then the answer is (1, 3). If you mean he starts at 1 on the X axis (horizontal line), then the answer is (0, 4)

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3 years ago

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The selling price of a television in a retail store is $66 less than 3 times the wholesale price. If the selling price

Anna71 [15]

Answer:

899 + 66 = 3*X, X being the wholesale price.

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Step-by-step explanation:

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3 years ago

Write 1.052 as a percent

valina [46]

The decimal 1.052 as a percent is 105.2%.

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4 years ago

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Subtract the following fractions.

yanalaym [24]

Answer:

22. 3/8

23. 3/5

24. 0

Step-by-step explanation:

turn the 1 into a fraction for each of the problems.

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8/8 - 5/8 = 3/8

try 23 and 24 now!

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3 years ago

Several terms of a sequence {an}n=1 infinity are given. A. Find the next two terms of the sequence. B. Find a recurrence relatio

s344n2d4d5 [400]

Answer:

A) $\frac{1}{1024},\frac{1}{4096}$

B) $\left\{\begin{matrix}a(1)=1 & \\ a(n)=a(n-1)*\frac{1}{4} &\:for\:n=1,2,3,4,... \end{matrix}\right.$

C) $\\a_{n}=nq^{n-1} \:for\:n=1,2,3,4,...$

Step-by-step explanation:

1) Incomplete question. So completing the several terms: $\left \{a_{n}\right \}_{n=1}^{\infty}=\left \{ 1,\frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},... \right \}$

We can realize this a Geometric sequence, with the ratio equal to:

$q=\frac{1}{4}$

A) To find the next two terms of this sequence, simply follow multiplying the 5th term by the ratio (q):

$\frac{1}{256}*\mathbf{\frac{1}{4}}=\frac{1}{1024}\\\\\frac{1}{1024}*\mathbf{\frac{1}{4}}=\frac{1}{4096}\\\\\left \{ 1,\frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},\mathbf{\frac{1}{1024},\frac{1}{4096}}\right \}$

B) To find a recurrence a relation, is to write it a function based on the last value. So that, the function relates to the last value.

$\left\{\begin{matrix}a(1)=1 & \\ a(n)=a(n-1)*\frac{1}{4} &\:for\:n=1,2,3,4,... \end{matrix}\right.$

C) The explicit formula, is one valid for any value since we have the first one to find any term of the Geometric Sequence, therefore:

$\\a_{n}=nq^{n-1} \:for\:n=1,2,3,4,...$

6 0

3 years ago

I am not able to solve this question​

I am not able to solve this question